Answer:
x=10(sum of angle of triangle by bringing 70 through alternate angle)
<EFY=65( putting value of x)
y=13(sum of angle of triangle by bringing 45 through alternate angle)
When car B passes car A, they will have traveled the same distance, d.
speed = distance/time
distance = speed * time
Car A travels t time.
Since car B starts an hour later, car B travels t - 1 time.
Car A:
d = st
s = 40t
Car B:
d = st
d = 60(t - 1)
The distance are equal, so
40t = 60(t - 1)
40t = 60t - 60
-20t = -60
t = 3
Car A started at 9 am.
9 am + 3 hours = noon.
Answer: at noon.
8n-4n = 4n
4n+ 2 = 4n
Subtract 4n from both sides
2= 0
No solutions
Answer is c
Explanation: pythagorean theorem
a^2+b^2=c^2
The transformation from parallelogram LMNO to parallelogram L'M'N'O' is a reflection across the x-axis
<h3>How to determine the transformation?</h3>
The complete question is added as an attachment
From the graph, we have the following highlights:
- Parallelogram LMNO and parallelogram L'M'N'O' are on either sides of the x-axis
- They are equidistant from the x and y axes
- They have equal dimensions
This means that parallelogram LMNO is reflected across the x-axis to get parallelogram L'M'N'O'
Hence, the transformation from parallelogram LMNO to parallelogram L'M'N'O' is a reflection across the x-axis
Read more about transformation at:
brainly.com/question/11709244
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