A right triangle has one angle equal to 90 degrees. A right triangle can also be an isosceles triangle--which means that it has two sides that are equal. A right isosceles triangle has a 90-degree angle and two 45-degree angles. This is the only right triangle that is an isosceles triangle. But the answer is right triangle
Solve:
"<span>twice the number minus three times the reciprocal of the number is equal to 1."
3(1)
Let the number be n. Then 2n - ------- = 1
n
Mult all 3 terms by n to elim. the fractions:
2n^2 - 3 = n. Rearranging this, we get 2n^2 - n - 3 = 0.
We need to find the roots (zeros or solutions) of this quadratic equation.
Here a=2, b= -1 and c= -3. Let's find the discriminant b^2-4ac first:
disc. = (-1)^2 - 4(2)(-3) = 1 + 24 = 25.
That's good, because 25 is a perfect square.
-(-1) plus or minus 5 1 plus or minus 5
Then x = ------------------------------ = --------------------------
2(2) 4
x could be 6/4 = 3/2, or -5/4.
You must check both answers in the original equation. If the equation is true for one or the other or for both, then you have found one or more solutions.</span>
The answer is A because the x has different numbers
In this question, we're trying to find the inequality that is true.
To find your answer, we can convert the numbers in the absolute value:
|−5| < 4:
5 < 4 <em>false</em>
|−4| < |−5|:
4 < 5 <em>true </em>
|−5| < |4|
5 < 4 <em>false</em>
|−4| < −5
4 < -5 <em>false</em>
The only true inequality here would be |−4| < |−5|, since it works with the inequality sign.
Answer:
|−4| < |−5|
Answer:

Step-by-step explanation:
The standard form of a quadratic is
. You need to subtract the x^2 from the right to set the quadratic equal to 0. Then a,b, and c are equal to the values of the coefficients in front of the terms.
If this helped, a brainliest would be greatly appreciated!