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Alinara [238K]
3 years ago
14

Find an explicit rule for the nth term of the arithmetic sequence

Mathematics
1 answer:
jekas [21]3 years ago
4 0
A(n)=a*r^n-1

n=term umber

A(n)= nth term

a=first term

r=common ratio

example: A(n)=a*r^n-1

r=4 a=2 n=9
A(9)=2*4^9-1
A(9)=2*4^8
A(9)=2*65,536
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What are the solutions to the system of equations?
svet-max [94.6K]

Answer:the third option is correct

Step-by-step explanation:

The system of equations are

y = 2x^2 - 5x - 7 - - - - - - - - - - -1

y = 2x + 2 - - - - - - - - - - - - - 2

We would equate equation 1 and equation 2. It becomes

2x^2 - 5x - 7 = 2x + 2

2x^2 - 5x - 2x - 7 - 2 = 0

2x^2 - 7x - 9 = 0

We would find two numbers such that their sum or difference is -7x and their product is - 18x^2. The two numbers are 2x and - 9x. Therefore

2x^2 + 2x - 9x - 9 = 0

2x(x + 1) - 9(x + 1) = 0

2x - 9 = 0 or x + 1 = 0

2x = 9 or x = - 1

x = 9/2 = 4.5

Substituting x = 4.5 or x = -1 into equation 2, it becomes

y = 2 × 4.5 + 2 or y = 2 × - 1 + 2

y = 11 or y = 0

Therefore, the solutions are

(4.5, 11) (- 1, 0)

6 0
4 years ago
Maya spent 40% of her savings to pay for a bicycle that cost $60 how much was in her savings​
Ahat [919]

Answer:

$150

Step-by-step explanation:

First use a proportion to find the answer:

40/100=60/x

Now we solve for x

60*100=6,000

6,000 divided by 40= 150

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Therefore the answer is $150

3 0
3 years ago
Lisa divided the irregular polygon into 2 rectangles with a line.
Bogdan [553]
Here's the link for the image: http://assets.openstudy.com/updates/attachments/5507589de4b01982d6668698-winsteria-1426544809579-ms_......

The correct is this one: "d. 3(9) + 7(5)." Lisa divided the irregular polygon into 2 rectangles with a line. The <span> expression that can be used to find the area of the irregular polygon is 3(9) + 7(5). That will give you the total are of the two rectangles.</span>
3 0
3 years ago
2x+3y+2z=13<br> 2y+z=1<br> z=3
Igoryamba
<h3>Given</h3>

z = 3

2y +z = 1

2x +3y +2z = 13

<h3>Find</h3>

x, y, z

<h3>Solution</h3>

... z = 3 is given

Substitute that into the second equation.

... 2y + 3 = 1

... 2y = -2 . . . . . subtract 3

... y = -1 . . . . . . . divide by the coefficient of y

Substitute these two solutions into the third equation.

... 2x +3(-1) +2(3) = 13

... 2x = 10 . . . . . . . . . . . .  collect terms, subtract 3

... x = 5 . . . . . . . . . . . . . . divide by the coefficient of x

The variable values are: x = 5, y = -1, z = 3

6 0
3 years ago
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Juli2301 [7.4K]
1/2 1/3 that's what I got
8 0
3 years ago
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