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kogti [31]
3 years ago
9

When researchers are measuring plant productivity, they usually harvest and measure above-ground biomass. But with grassland pla

nts, it is common to find that most of an individual's biomass is in its root system. Why don't researchers measure below-ground biomass as well?
Biology
1 answer:
LekaFEV [45]3 years ago
6 0

Answer:

Because of the fibrous root network of grasses.

Explanation:

<em>Measuring below ground biomass of grass plants is technically impossible and difficult because of the fibrous root network different plants form with one another and within the soil. The network virtually makes it impossible to individually extract all the underground biomass of each grass.</em>

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A population of wild-flowers was scored for flower color. There were 302 blue (BB) plants, 1857 violet (BR) plants and 811 red (
Lina20 [59]

Answer:

Explanation:

Hardy and Weinberg described all the possible genotypes for a gene with two alleles. The binomial expansion representing this is, p2 + 2pq + q2 = 1.0

Where,

p2 = proportion of homozygous dominant individuals (BB) = 313

q2 = proportion of homozygous recessive individuals (RR) = 857

2pq = proportion of heterozygotes (BR) = 1820

The proportion of BB individuals in the population is = 313/2990 = 0.1046

The proportion of BR individuals in the population is = 1820/2990 = 0.6086

The proportion of RR individuals in the population is = 2/82 = 0.2866

I).

a). The frequency of p allele in the population is, (B) = p2 + 1/2(2pq) = 0.1046 + ½ (0.6086) = 0.4089

b). The frequency of q allele in the population is, (R) = q2 + 1/2(2pq) = 0.2866 + ½ (0.6086) = 0.5909.

II).

The expected number of individuals with the BB genotype = 0.4089* 0.4089 = 0.1671*2990 = 499.6 = 500

The expected number of individuals with the BR genotype = 2*0.4089* 0.5909 = 0.4832*2990 = 1444.768 = 1445

The expected number of individuals with the RR genotype = 0.5909*0.5909 = 0.3491*2990 = 1043.809 = 1044

CHI - SQUARE (X2):

X2 = Σ(O - E)2 / E

Where O = Observed frequency

E = Expected frequency

Phenotype    O              E          (O-E)         (O-E)^2             (O-E)^2/E

BB                313           500      -187            34969             69.938

BR              1820         1445      375           140625           97.31834

RR              857           1044       1.5            2.25                0.155172

                2990       2989      189.5                                 167.4115

The calculated Chi-square value is = 167.4115

Degrees of freedom is = n-1 = 3-1 = 2

The P-value is < 0.00001, which is significant at p < 0.05. So, we reject the null hypothesis.

Conclusion: There is a significant difference between the observed and expected values.

5 0
3 years ago
How is biodiversity important to the medical and pharmaceutical industries?
ladessa [460]

Answer:

The preservation of biodiversity provides a vital link to critically expand the molecular diversity necessary for successful drug discovery efforts in the future. ... This ongoing loss of biodiversity is altering ecosystem functions and the ability to provide goods and services for human health and well-being

Explanation:

8 0
3 years ago
Mike and Ike swabbed the surface of their lab bench to see what bacteria were present. They transferred the swab contents to the
Delvig [45]

ok from smallest to largest it's:

atom -> molecule -> macromolecule -> organelle -> cell -> tissue -> organ -> system -> organism -> population -> community -> ecosystem -> biosphere

I think a population involves <u>only a single species.</u>

But it looks like the Petri dish has several species of bacteria.

So I would say it's 1 level higher and that the answer is community.

4 0
3 years ago
How does photosynthesis affect multiple levels of life?
torisob [31]
 Cellular respiration uses oxygen and generates carbon dioxide. Photosynthesis uses carbon dioxide and generates oxygen.  Its a cycle.
4 0
3 years ago
The pedicles laminae and spinous process form what
Sonja [21]
Together they form t<span>he vertebral arch.

</span>The vertebral arch is a<span> component of a typical vertebra. It is the posterior part of the vertebral body, formed by pedicles, vertebral laminae, the spinous process </span>and the base of the articular processes. This arch defines the vertebral foramen, where the spinal cord passes.


3 0
4 years ago
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