2 years ago

F(x) = 5x^2 - 8x - 5 what is the value of f(10) ?

1 answer:

8 0

f '(x) = 2(3x2 + 5) + 6x(2x - 1)= 6x2 + 10 + 12x2 - 6x= 18x2 - 6x + 10

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Solve 5r2 – 12 = 68. {±4} {±5} {±3} {±6}

sashaice [31]

Hey there!

Assuming you meant

$5r^2 - 12 = 68$

If so, follow these steps so it can be a little bit easier to solve

Firstly, we have to $add$ by $12$ on each of your sides

$5r^2 -12 +12 \\ \\ 68 + 12$

$5r^2 = 5r^2 \\ \\ 68 + 12 = 80$

We get: $5r^2 =80$

Now, we have $divide$ by $5$ on each of your sides

$\frac{5r^2}{5} = \frac{80}{5}$

$\frac{80}{5} = 16$

We get: $r^2 = 16$

$r =$ ± $\sqrt{16}$

Therefore , your answer is: $r =$ ± $4$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

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2 years ago

HELPPPP!!!!! what is the y-intercept of the parabola y = x2 + 6x .

Natali [406]

The y intercept is what we get when x=0, so in this case it's

Answer: y=0

3 0

2 years ago

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Write a word phrase for c – 9.1. 9.1 less than a number a number subtracted from 9.1 a number plus 9.1 9.1 minus a number

xxTIMURxx [149]

9.1 minus a number is correct

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2 years ago

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86,921 in expanded form

Rudik [331]

86921 = 80000 + 6000 + 900 +20 +1

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2 years ago

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¿cuál es el vértice de una parábola que corta los ejes en los puntos (-1,0) , (5,0), (0,-10) ?

kvasek [131]

Answer:

vertex: (2,-18)

Step-by-step explanation:

y = ax² + bx + c

(-1,0) : a - b + c = 0 ...(1)

(5,0) : 25a +5b +c = 0 ...(2)

(0,-10): 0a + 0b + c = -10 c=-10

(1) x5: 5a - 5b + 5c = 0 ...(3)

(2)+(3): 30a + 6c = 0 30a = -6c = 60 a = 2

(1): 2 - b -10 = 0 b = -8

Equation: y = 2x² - 8x -10 = 2 (x² -4x +4) - 18 = 2(x-2)² -18

equation: y = a(x-h)²+k (h,k): vertex

vertex: (2,-18)

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2 years ago