Answer:
m = $14/day
w = $6/day
Step-by-step explanation:
See attached image.
Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
So u have to add all the sides up.
which will give you 6 + 6√3 + 6 +6√3
because their opposite and parallel lengths and widths are equal
that gives you 12 + 12√3
so ans is 12m + 12√3m
(3+11i)/(3+11i)=1
So that means you can multiply 6/(3+11i) by (3+11i)/(3+11i)
Then 6(3+11i)/1
= 18+66i
Answer:
19.2
Step-by-step explanation:
12 squared + 15 squared= C squared
144 + 225 = C squared
369 = C squared
Do square root of 369, which is
19.2
