To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
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The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Multiply both sides by 2
(2) 18 = x/2 (2)
the /2 (2) gets canceled out
so it's 36= x
Hope this helps
Well first lets add up all the students to see how many there are to split.
22 + 26 = 48
Now, let's split that into four groups.
48/4 = 12
So there will be 12 people in each group.
