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kompoz [17]
3 years ago
6

Jenny recorded the weight of 5 dogs. Each dog weighed a different amount. She recorded the results

Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0

Answer:

C

Step-by-step explanation:

the middle 50% wold be the numerical values in the actual box part of the box plot.

Solnce55 [7]3 years ago
4 0
The answer is C loll
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One way to prove this quadrilateral is a square is by calculating the slopes of its sides and the slopes of its diagonals.
tatuchka [14]

Answer:

Step-by-step explanation:

<h3>To prove quadrilateral is a square:</h3>

a)  Slope of CB

   C(-3,-1)  ; B = (0,3)

     \sf \boxed{Slope = \dfrac{y_2-y_1}{x_2-x_1}}

                \sf = \dfrac{3-[-1]}{0-[-3]}\\\\ =\dfrac{3+1}{0+3}\\\\ = \dfrac{4}{3}

  \sf \text{\bf slope of CB = $\dfrac{4}{3}$}

b) D(1,-4)   ; A(4,0)

    Slope \ of \ DA = \dfrac{0-[-4]}{4-1}\\

                          = \dfrac{0+4}{3}\\\

    \sf \text{\bf Slope of DA = $\dfrac{4}{3}$}

Slope of CB = slope of DA

c) C(-3,-1) ; D(1 , -4)

    \sf Slope \ of \ CD =\dfrac{-4-[-1]}{1-[-3]}

                       \sf = \dfrac{-4+1}{1+3}\\\\    = \dfrac{-3}{4}\\

\sf Slope \ of \ CD * Slope of CB =  \dfrac{-3}{4}*\dfrac{4}{3}=-1

So, CD is perpendicular to   CB

d) B(0,3)  ;  D(1,-4)

    Slope \ of \ BD = \dfrac{-4-3}{1-0}\\\\=\dfrac{-7}{1}\\\\=-7

e) C(-3,-1) ; A(4,0)

   \sf Slope \ of \ CA = \dfrac{0-[-1]}{4-[-3]}\\

                       =\dfrac{0+1}{4+3}\\\\=\dfrac{1}{7}

\text{Slope of CA *Slope of BD = $\dfrac{1}{7}$*(-7)}=-1

So, CA is perpendicular to BD

\sf \text{\bf Slope of DA = \dfrac{4}{3}}

5 0
2 years ago
Simplify.<br> (5+squartrt3)2<br><br><br> 25 + sqrtrt10<br> 10 + 28sqrtrt3<br> 28 + 10sqrtrt3
SSSSS [86.1K]

Answer:

Step-by-step explanation:

If the 2 is an exponent, it needs to be written as ^2.

(5+√3)²  = 5² + 10√3 + 3 = 28 + 10√3

5 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=3%5E%7Bx%7D%20%3D%20%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="3^{x} = \frac{1}{9}
Makovka662 [10]

~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 3^x=\cfrac{1}{9}\implies 3^x=\cfrac{1}{3^2}\implies 3^x=3^{-2}\implies x = -2

8 0
2 years ago
There are 4, 6, and 7 points on three lines. How many quadrilaterals is it possible to create with given points as vertices?
Dmitry [639]

Answer:

Step-by-step explanation:If you choose any 3 of the 7 vertices, you can connect them with lines to create a unique triangle.

So, the question becomes "In how many different ways can we select 3 vertices from 7 vertices?"

Since the order in which we select the 3 vertices does not matter, we can use COMBINATIONS.

We can select 3 vertices from 7 vertices in 7C3 ways.

5 0
3 years ago
Let x and y be inversely related such that y = 2 when x = 5. Find y when x = 15
Arturiano [62]

Answer:

y would be 6

Step-by-step explanation:

Because 5 x 3 would be 15

then you would do 2 x 3 would be 6

5 0
3 years ago
Read 2 more answers
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