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Zielflug [23.3K]
2 years ago
8

Can someone please help me with this

Mathematics
1 answer:
postnew [5]2 years ago
7 0
<h2>1.</h2><h3>1)</h3>

Put the given values of p and q in the factored form equation.

... f(x) = (x -(-1))(x -(-2)) . . . . p and q values put in

... f(x) = (x +1)(x +2) . . . . . . .simplified

<h3>2)</h3>

Multiplying the factors, we have

... f(x) = x(x +2) + 1(x +2) = x² +2x +1x +2

... f(x) = x² +3x +2

<h2>2.</h2>

We want to factor x³ -x² -6x. We notice first of all that x is a factor of all terms. Thus we have

... = x(x² -x -6)

Now, we're looking for factors of -6 that add up to -1. Those are -3 and 2. Thus the factorization is ...

... = x(x -3)(x +2)

<h2>3.</h2>

We want a description of the structure and an equivalent expression for

... 64x⁹ -216

We note that 64, 216, and x⁹ are all cubes, so this expression is ...

... the difference of cubes.

It can be rewritten to

... = 8((2x³)³ -3³)

and so can be factored as

... = 8(2x³ -3)(4x⁶ +6x³ +9)

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what do question I didn't get it

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The slope of the line that passes through points -2,3 and 10,3 is
Ray Of Light [21]

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i gave you the slope and if its a function

Step-by-step explanation:

it a function  

Slope (m) = ΔYΔX= 0

θ = arctan( ΔY )ΔX= 0°

ΔX = 10 – -2 = 12

ΔY = 3 – 3 = 0

Distance (d) = √ΔX2 + ΔY2 = √144 = 12

Equation of the line:

y = 0x + 3

When x=0, y = 3

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Helpppp pleaseee ! i don’t understand
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I suck at this type of math because the teacher did not explain good enough and I’m stuck.
lisabon 2012 [21]

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21

Step-by-step explanation:

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<3

Red

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3 years ago
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What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0
Tom [10]

Answer:

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

Step-by-step explanation:

The given equation is

(2x+3)^2+8(2x+3)+11=0

Let us treat this as a quadratic equation in (2x+3).

where a=1,b=8,c=11

The solution is given by the quadratic formula;

(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}

We substitute these values into the formula to obtain;

(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}

(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}

(2x+3)=\frac{-8\pm \sqrt{20} }{2}

(2x+3)=\frac{-8\pm2\sqrt{5} }{2}

(2x+3)=-4\pm \sqrt{5}

(2x+3)=-4-\sqrt{5} or (2x+3)=-4+ \sqrt{5}

2x=-3-4-\sqrt{5} or 2x=-3-4+ \sqrt{5}

2x=-7-\sqrt{5} or 2x=-7+ \sqrt{5}

x=\frac{-7-\sqrt{5}}{2} or x=\frac{-7+ \sqrt{5}}{2}

5 0
3 years ago
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