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algol [13]
3 years ago
7

Need help ASAP please please answer me the question give brainliest to write answer ​

Mathematics
1 answer:
lora16 [44]3 years ago
7 0

Answer:

the answer is -0.5

pls mark me in brainliest

Step-by-step explanation:

i hope it will help u

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For what value of x is r(x)= -21??
Naily [24]

Answer:

Rx= - 21

Rx/r= - 21/r

X=-21/r

4 0
1 year ago
As part of a screening process, computer chips must be operated in an oven at 145 °C. Ten minutes after starting, the temperatur
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I solved this using initial conditions and calculus, so I hope that's what you are doing in math.  It's actually NOT calculus, just a concept that is taught in calculus.

The initial condition formula we need is

y=Ce^{kt}

Filling in our formula with the 2 conditions we are given:

65=Ce^{10k}   and   85=Ce^{15k}

With those 2 equations, we have 2 unknowns, the C (initial value) and the k (the constant). We know that the initial value (or starting temp) for both conditions is the same, so we solve for C in one equation, sub it into the other equation and solve for k.  If

65=Ce^{10k} then

\frac{65}{e^{10k}}=C which, by exponential rules is the same as

C=65e^{-10k}

Since that value of C is the same as the value of C in the other equation, we sub it in:

85=65e^{-10k}(e^{15k})

Divide both sides by 65 and use the rules of exponents again to get

\frac{85}{65}=e^{-10k+15k} which simplifies down to

\frac{85}{65}=e^{5k}

Take the natural log of both sides to get

ln(\frac{85}{65})=5k

Do the log thing on your calculator to get

.2682639866 = 5k and divide both sides by 5 to find k:

k = .0536527973

Now that we have k, we sub THAT value in to one of the original equations to find C:

65=Ce^{10(.0536527973)}

which simplifies down to

65=Ce^{.536527973}

Raise e to that power on your calculator to get

65 = C(1.710059171) and divide to solve for C:

C = 38.01038064

Now sub in k and C to the final problem when t = 23:

y=38.01038064e^{(.0536527973)(23)} which simplifies a bit to

y=38.01038064e^{1.234014338}

Raise e to that power on your calculator to get

y = 38.01038064(3.434991111) and

finally, the temp at 23 minutes is

130.565

6 0
3 years ago
Rachel has a bag of fruit that has a mass of 50 hectograms. Rachel converts this mass to centigrams. Her work is shown below.
Alinara [238K]

Answer:

She should have multiplied by 10,000

Step-by-step explanation:

Given table:

\begin{array}{| c | c |}\cline{1-2} \sf kilo & 1,000 \\\cline{1-2} \sf hecto & 100 \\\cline{1-2} \sf deka & 10 \\\cline{1-2} \sf unit & 1 \\\cline{1-2} \sf deci & 0.1 \\\cline{1-2} \sf centi & 0.01 \\\cline{1-2} \sf milli & 0.001 \\\cline{1-2}\end{array}

To find the conversion rate:

\sf \dfrac{hecto}{centi}=\dfrac{100}{0.01}=10000

Therefore, 1 hectogram = 10,000 centigrams

So when converting hectograms to centigrams, multiply the mass by 10,000.

⇒ 50 hg × 10,000 = 500,000 centigrams

Rachel's error was that she should have multiplied by 10,000.

7 0
2 years ago
Read 2 more answers
Four oranges cost a total of 90 cents. At this rate, what is the cost of 3 dozen oranges? Step by step will put brilliants
allsm [11]
Four oranges cost 90 cents, an orange costs 90/4 cents, which is around 22.5 cents. Multiply this by 36 to get the cost of 3 dozen oranges, so 22.5 times 36 is 810, 810 cents, or 8.10 dollars.
8 0
3 years ago
Read 2 more answers
Help please! Ty! Ratios
Kamila [148]

Answer:

Ratios to roses to lilies....6:9

Reduced.....2:3

Step-by-step explanation:

Pretty simple doesn't need explaining

8 0
3 years ago
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