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3 years ago

10

For the parallelogram, find the value of the variables. Show your work

1 answer:

gayaneshka [121]3 years ago

6 0

The opposite sides on a parallelogram have equal side lengths. Assuming that your drawing is supposed to contain those expressions and values on opposite sides, 5x + 2 is opposite of 17, and 3y - 6 is opposite of 21, so we equate them:
5x + 2 = 17
x = 3
Similarly, 3y - 6 = 21
y = 9

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Help with top one please

HACTEHA [7]

Short answer: 39
y = 7x - 3
f(x) = y = 7x - 3 Though there are some slight differences between f(x) and y, it is safe to say that f(x) acts (in this case) as a y value. So the question now is what does y(6) mean?

y(6) means exactly the same thing as what f(6) would mean. The both mean that where ever you see an x, put in a 6.

So y(6) means 7x - 3 = 7*6 - 3 = 39

5 0

3 years ago

Read 2 more answers

Subtract 8 y^2 − 5 y + 7 from 2 y^2 + 7 y + 1 1 <br><br> The answer is: −6y ^2 +12y+4

lys-0071 [83]

Answer:

$\large\boxed{-6y^2+12y+4}$

Step-by-step explanation:

$(2y^2+7y+11)-(8y^2-5y+7)\\\\=2y^2+7y+11-8y^2-(-5y)-7\\\\=2y^2+7y+11-8y^2+5y-7\qquad\text{combine like terms}\\\\=(2y^2-8y^2)+(7y+5y)+(11-7)\\\\=-6y^2+12y+4$

4 0

4 years ago

An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha

natita [175]

Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

$H_o: \mu = 7.1$

The alternative hypothesis:

$H_a: \mu > 7.1$

This test is right-tailed.

$degree \ of \ freedom= n - 1 \\ \\ degree \ of \ freedom = 24 - 1 \\ \\ degree \ of \ freedom = 23$

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test $t_c = 2.069$

The test statistics can be computed as:

$t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}$

$t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}$

$t = \dfrac{0.2}{0.204}$

t = 0.980

Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < $t_c = 2.069$ , then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

6 0

3 years ago

What are the first five sequences to the equation f(1)=2/3,f(n)=f(n-1)x3/2

iren [92.7K]

Answer:

2/3,1,3/2,9/4,27/8

Step-by-step explanation:

f(1)=2/3

f(n)=f(n-1)×3/2

f(2)=f(2-1)×3/2=f(1)×3/2=2/3×3/2=1

f(3)=f(3-1)×3/2=f(2)×3/2=1×3/2=3/2

f(4)=f(4-1)×3/2=f(3)×3/2=3/2×3/2=9/4

f(5)=f(5-1)×3/2=f(4)×3/2=9/4×3/2=27/8

7 0

3 years ago

-12 - 6p - (-2) combining like terms with negative coefficients

vlada-n [284]

- 12 - 6p - (-2) =

= - 12 - 6p + 2

= - 10 - 6p

= - 2(5 + 3p)

4 0

3 years ago