Answer:
Smooth & yellow: 9
smooth & green: 3
wrinkled & yellow: 3
wrinkled & green: 1
Explanation:
Gene controlling seed color are yellow Vs green
Gene controlling seed texture are smooth Vs wrinkled
In F1 generation, A true breeding smooth green plant (SSyy) is crossed to a true breeding wrinkled yellow (ssYY)
Off spring in F1 generation are smooth yellow (SsYy)
This means smooth texture is dominant over wrinkled texture and yellow color is dominant over green
in F2 generation, the cross is carried between SsYy
SY Sy sY sy
SY SSYY SSYy SsYY SsYy
Sy SSYy SSyy SsYy Ssyy
sY SsYY SsYy ssYY ssYy
sy SsYy Ssyy ssYy ssyy
Smooth & yellow: 9
smooth & green: 3
wrinkled & yellow: 3
wrinkled & green: 1
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
Elements that have atoms with full outer shells of electrons
Are inert
Answer:
there were only anaerobic heterotrophic bacteria (the primordial atmosphere was virtually oxygen-free).
