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ololo11 [35]
3 years ago
15

Diurnal are common orchids found in Australia the flowers of this species display a large number of varieties in color and makin

gs insects rely on the ability to learn the specific colors and markings of unfavorable flowers to avoid them in the future.

Biology
1 answer:
Gwar [14]3 years ago
5 0

Answer:

A

Explanation:

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Metamorphic rock formation from sedimentary rocks is caused by heat and pressure. After millions of years in transformation, the
kap26 [50]

Answer:

C) layering, directional pressure

Explanation:

The foliated metamorphic rocks are those rocks subjected to heat and pressure during metamorphism, characterized by presenting a parallel alignment of minerals, which gives the rock an appearance of layers or bands.

7 0
4 years ago
A sedimentary rock that is composed of material evaporated from seawater is called?
charle [14.2K]
A chemical sedimentary rock?
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4 years ago
Why do organisms die if they don’t have enough water
Alla [95]
The transfers of most cells require water and if the body dosent have enough it will shut down
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3 years ago
What happens when the parasympathetic nervous system is activated
kolezko [41]

Answer:

Body functions stimulated by the parasympathetic nervous system (PSNS) include sexual arousal, salivation, lacrimation, urination, digestion, and defecation. The PSNS primarily uses acetylcholine as its neurotransmitter. Peptides (such as cholecystokinin) may also act on the PSNS as neurotransmitters. The parasympathetic nervous system is composed mainly of the cranial and sacral spinal nerves.

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6 0
3 years ago
If C-1 of glucose is radiolabeled and the glucose then enters glycolysis, what percentage of the pyruvate molecules will carry t
Talja [164]

Answer:

50%

Explanation:

Glucose is a simple sugar with a total of 6 carbon atoms in its structure. Pyruvate has a total of three carbon atoms. Two molecules of pyruvate are obtained per glucose by glycolysis.  None of the carbon of glucose is released in the form of CO2 during glycolysis. Therefore, the radio-labeled C-1 of glucose will be the component of the carbon skeleton of one of the total of two pyruvate molecules produced during glycolysis. So, 50% of the pyruvate will exhibit radioactivity.

5 0
3 years ago
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