Answer:
8.55 × 
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given:
Fifth term of a geometric sequence = 
Common ratio (r) = ¼
Required:
Formula for the nth term of the geometric sequence
Solution:
Step 1: find the first term of the sequence
Formula for nth term of a geometric sequence =
, where:
a = first term
r = common ratio = ¼
Thus, we are given the 5th term to be ¹/16, so n here = 5.
Input all these values into the formula to find a, the first term.




Cross multiply

Divide both sides by 16



Step 2: input the value of a and r to find the nth term formula of the sequence
nth term = 
nth term = 

Answer:
B.
Step-by-step explanation:
Trust me.
I just did it.
Answer:
The value is 
Step-by-step explanation:
The diagram illustrating the question is shown on the first uploaded image
From the question we are told that
The distance from city A to B is AB = 467.3 miles
The bearing from B to C is 
The bearing from B to A is 
The bearing from A to B is 
The bearing from A to C is 
Generally from the diagram

=> 
Also

and

=> 
=> 
Generally according to Sine Rule

=>
So

=> 
Also


Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as
![k = [CA +BC] - AB](https://tex.z-dn.net/?f=k%20%3D%20%5BCA%20%2BBC%5D%20%20-%20AB%20)
=> ![k = [260 .1 +316.8]- 467.3](https://tex.z-dn.net/?f=%20k%20%3D%20%5B260%20.1%20%2B316.8%5D-%20467.3%20)
=> 
Answer:
111°
Step-by-step explanation:
The two angles are alternate exterior angles, and those types of angles are always congruent if there are parallel lines.