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velikii [3]
4 years ago
14

A hollow ball is made of rubber that is 2 centimeters thick the ball has a radius to the outside surface of 6 cm what is the app

roximate volume of rubber used to make the ball
Mathematics
1 answer:
Fudgin [204]4 years ago
4 0
The answer would be 636.4 cm3 because you first have to find the volume of the sphere including the rubber wall, which is 904.32 cm3. Next, you would find the volume of the sphere inside the rubber, so subtract 2 cm from the radius of 6 cm and put 4 cm into the formula to get 267.9567. Last, subtract the internal volume from the external volume to get 636.3733 cm3 and round it to the tents place.
(4/3) x 3.14 x 6^3 = 904.32
(4/3) x 3.14 x 4^3 = 267.9467
904.32 - 267.9467 = 636.3733
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tino4ka555 [31]

Answer:

\large\boxed{x=\dfrac{1}{2}-\sqrt2\ or\ x=\dfrac{1}{2}+\sqrt2}

Step-by-step explanation:

\text{The quadratic formula of}\ ax^2+bx+c=0:\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{We have:}\\\\4x^2-7=4x\qquad\text{subtract}\ 4x\ \text{from both sides}\\\\4x^2-4x-7=0\\\\a=4,\ b=-4,\ c=-7\\\\b^2-4ac=(-4)^2-4(4)(-7)=16+112=128\\\\\sqrt{b^2-4ac}=\sqrt{128}=\sqrt{64\cdot2}=\sqrt{64}\cdot\sqrt2=8\sqrt2\\\\x=\dfrac{-(-4)\pm8\sqrt2}{(2)(4)}=\dfrac{4\pm8\sqrt2}{8}\qquad\text{simplify by 4}\\\\x=\dfrac{1\pm2\sqrt2}{2}\to x=\dfrac{1}{2}\pm\sqrt2

6 0
3 years ago
Solve the following system of equations:<br> y = 5/4x - 2<br> y = -1/4x + 19<br><br> x = ? and y = ?
Dmitry [639]

Answer:

1. y= 5 /4 x −2

2.x=−4y+76

4 0
3 years ago
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linda is building a rectangular playhouse. the width is x feet. the length is x + 3 the distance around the base of the playhous
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No. The value of x is 7.5 feet.
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3 years ago
EFV and EDW are straight lines.<br>Find the value of x and of y.​
Makovka662 [10]

Answers:

x = 72

y = 83

============================================================

Explanation:

Angle VFG is 50 degrees. The angle adjacent to this is angle EFG which is 180-50 = 130 degrees.

Angle HDW is 77 degrees. The supplementary angle adjacent to this is 180-77 = 103 degrees which is angle EDH.

Pentagon EFGHD has the following five interior angles

  • E = x
  • F = 130
  • G = 170
  • H = 65
  • D = 103

Note that angles F = 130 and D = 103 were angles EFG and EDH we calculated earlier.

For any pentagon, the interior angles always add to 180(n-2) = 180(5-2) = 180*3 = 540 degrees.

This means,

E+F+G+H+D = 540

x+130+170+65+103 = 540

x+468 = 540

x = 72

---------------------------------------

Now focus your attention on triangle THS

We see that the interior angles are

  • T = y
  • H = 65
  • S = 32

The angle H is 65 degrees because it's paired with the other 65 degree angle shown. They are vertical angles.

For any triangle, the angles always add to 180

T+H+S = 180

y+65+32 = 180

y+97 = 180

y = 180-97

y = 83

7 0
3 years ago
X over 2 +2= 15 two step equations
Fed [463]

Answer:

\boxed{\boxed{\sf x=84}}

Step-by-step explanation:

\sf \cfrac{x}{6} +2=16

<u>Multiply both sides of the equation by 6:</u>

\sf x+12=96

<u>Subtract 12 from both sides:</u>

\sf x=96-12

<u>Subtract 12 from 96:</u>

\sf x=84

<u>_________________________________</u>

3 0
2 years ago
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