Answer:
Explanation has been given below
Step-by-step explanation:
a) inter arrival times are exponentially distributed with mean 1/n , where n = rate = 1/sec.
probability distribution function is F(t)=n*exp(-n*t).
reference to any kth packet and the (k-1)th packet
the answer is = integration of F(t).dt with limits 0 to 2 = 1 - exp(-2*n) = 1 - exp(-2)
b) t=5 , P(q) = exp(-5)*(5)^q/factorial(q)
probability of fourth call within t=5 seconds is =
that is P(4) P(5) ...... = 1 - ( P(0) P(1) P(2) P(3) ) ; put the values and get the answer.
c) number of calls/rate = 4/n = 4 seconds
Answer:
A
Step-by-step explanation:
Answer:
(-2,-2)
Step-by-step explanation:
for question number 15...cordinated grid shows each equation...first equation is represented by straight line going upwards through +4 in y axis...(y=3x+4)...
point is....every point in this two lines represent a possible x and y value for each equation...and there is a point where these lines meet each other....in that point...x and y values are possible values for both equations.so answer is (-2,-2)...this cordination satisfy each pairs of equation...you can try using -2 for x in both equations and get -2 as the answer for y...that proves the point..try it for 16 quiz.good luck
Answer:
C
Step-by-step explanation:
There are same number on -2, -1 1 ,2
and it also means that 0,0 is the minime
Answer:
The median weight for shelter A is greater than that for shelter B.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.
