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Leviafan [203]
3 years ago
8

A GE Lightbulb is suppose to last for 1200 hours. In fact light bulbs of this type last only 1,185 hours with a standard deviati

on of 70 hours. What is the probability that a randomly selected light bulb will have an average life of at least 1,200?
Mathematics
1 answer:
Andre45 [30]3 years ago
8 0
This can be solved using the formula for t test which is = x - mu over standard deviation divided by the square root of the number of samples. In this case, it is 1185 - 1200 over 70 divided by square root of 100 which give us a value of 2.14 which is equal to .9839 in area. Only rarely, just over one time in a hundred tries of 100 light bulbs, would the average life exceed 1200 hours.
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How many whole numbers are there, whose squares and cubes have the same number of digits?
Naddik [55]

Answer:

there are only 4 whole numbers whose squares and cubes have the same number of digits.

Explanations:

let 0, 1, 2 and 4∈W (where W is a whole number), then

0^2=0, 0^3=0,

1^2=1, 1^3=1,

2^2=4, 2^3=8,

4^2=16, 4^3=64.

You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits







7 0
2 years ago
What is an ordinary annuity?
masha68 [24]

Answer:

An ordinary annuity is a series of equal payments made at the end of consecutive periods over a fixed length of time. The opposite of an ordinary annuity is an annuity due, in which payments are made at the beginning of each period.

Step-by-step explanation:

7 0
3 years ago
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What is the volume of the L block
Aneli [31]
This will help u
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4 0
2 years ago
Can somebody please help?
RUDIKE [14]

Answer:

it would already be 5.5 so then you add 2.2

Step-by-step explanation:


6 0
3 years ago
Can someone find r please
katrin2010 [14]

Answer:

r = 3 \times \sqrt{2}

Step-by-step explanation:

The area of the square is 36.

A = s^2

36 = s^2

s = sqrt(36)

s = 6

The side of the square has length 6.

All sides of a square are congruent, so all sides have length 6.

If you extend segment JO to point L, you end up with segment JL which is a diameter of the circle and the diagonal of the square. We can use the Pythagorean theorem using two sides if the square as legs and the diagonal of the square as the hypotenuse of a right triangle.

a^2 + b^2 = c^2

6^2 + 6^2 = c^2

36 + 36 = c^2

c^2 = 72

c = \sqrt{72}

c = \sqrt{36 \times 2}

c = \sqrt{36} \times \sqrt{2}

c = 6 \times \sqrt{2}

c is the diameter.

r is the radius, so it is half of the diameter.

c = d

r = d/2

r = \dfrac{d}{2} = 3 \times \sqrt{2}

8 0
3 years ago
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