Answer:
When point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).
i.e A'(0, 1) is the image of point A after a reflection.
Hence, point A is reflected across the x-axis.
Step-by-step explanation:
When we reflect a point A across the x-axis, the value of 'y' gets negated, but the value of 'x' remains unchanged.
In other words, when point P with coordinates (x, y) is reflected across the x-axis and mapped onto point P', the coordinates of P' will be (x, -y).
Thus, the rule is:
P(x, y) → P'(x, -y)
Thus, when point A with coordinates (0, -1) is reflected across the x-axis and mapped onto point A', the coordinates of A' will be (0, 1).
i.e A'(0, 1) is the image of point A after a reflection.
Hence, point A is reflected across the x-axis.
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Answer:
C) Reflection about the origin
Step-by-step explanation:
DE points to the right and slightly down. D'E' points to the left and slightly up. The segments are parallel, not perpendicular, so represent a rotation of 180°, not 90°. If the figure were subject only to translation, these segments would point in the same direction.
The transformation is a reflection about the origin (C). (This is equivalent to a rotation of 180°.)
Answer:
4,5,6
Step-by-step explanation:
*The sign of ≥ means that it must be greater or equal to 10 in this case
1). 3 isn't a possible solution due to 9 being less than 10
3+6_10
9_10
9<10
2). 4 is a possible solution due to the sum of 4 and 6 being equal to 10
4+6_10
10_10
10=10
3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10
5+6_10
11_10
11>10
4).6 is a possible solution due to the sum of 6 and 6 being larger than 10
6+6_10
12_10
12>10
Hope this helped! (:
Answer:
parallelograms
Area = base * height
Rhombus Area = Product of the diagonals
Trapezoid Area = median * height
