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faltersainse [42]
2 years ago
11

What is the perimeter?

Mathematics
2 answers:
Ad libitum [116K]2 years ago
7 0

Answer:

The perimeter is 92 ft

Step-by-step explanation:

Add all of the sides up

swat322 years ago
4 0

Answer:

92

Step-by-step explanation:

The perimeter is the length of the outline of a shape. To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. x is in this case the length of the rectangle while y is the width of the rectangle 12+12=24 and 40+28=68 and 68+24 is 92 so the answer is 92

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Determine whether quantities vary directly or inversely and find the constant of variation. An employee earns $175 for 15 hours
Vitek1552 [10]

Answer:

210 dollars in 18 hours

Step-by-step explanation:

175 / 15 = 11.6666666667

11.6666666667 times 18 equals 210 dollars

6 0
3 years ago
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NEED ANSWER ASAP (with work) <br><br> the diagram below shows a pentagon. Find the value of X.
Vera_Pavlovna [14]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Match the expressions with their equivalent simplified expressions.
Tasya [4]

Answer:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}


Step-by-step explanation:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}

\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}

\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}

\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}

\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}

\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}

Thus,

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}

3 0
3 years ago
Which of the following is the general term for the sequence a, -a, a, -a, . . . ?
Nataly_w [17]

Answer:

a(-1)^(n-1).

Step-by-step explanation:

This is a Geometric Sequence with common ratio r = -1.

The general term is a(-1)^(n-1).

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SOMEONE PLEASE HELP ME 3/4(x+4)=1/4(x+8)
Troyanec [42]

Answer:

x=-2

Step-by-step explanation:

To solve this equation, we can use PEMDAS or Order of Operations.

Parenthesis

Exponents

Multiplication>Division

Addition>Subtraction

Using the various properties can also help make the equation easier.

First, solve for parenthesis using the distributive property.

Our equation is now : 3/4x+3=1/4x+2

Now, subtract 2 on both sides, to cancel out the positive 2 on the right.

3/4x+1=1/4x

Now subtract 3/4x from both sides.

1=-2/4x

Finally, to isolate x, divide both sides by -2/4

1/-2/4=-2

x=-2

Hope this helps!

5 0
2 years ago
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