Answer:
x = 3 or x = -2
Step-by-step explanation:
Solve for x over the real numbers:
(x + 2) (x - 3) = 0
Hint: | Find the roots of each term in the product separately.
Split into two equations:
x - 3 = 0 or x + 2 = 0
Hint: | Look at the first equation: Solve for x.
Add 3 to both sides:
x = 3 or x + 2 = 0
Hint: | Look at the second equation: Solve for x.
Subtract 2 from both sides:
Answer: x = 3 or x = -2
Answer:
150°
Step-by-step explanation:
to find the individual angle of a REGULAR dodecagon (which means that all sides are equal), you'd use the equation I(individual angle)= (n-2)×180/n
N is number of sides. The number of sides on a dodecagon is 12. So, substitute N for 12
I= (12-2)×180/12 which simplifies to 10×180/12
10×180= 1800
1800/12 = 150
so, an individual interior angle of a dodecagon is 150°
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
Answer:
1,500 tickets in total (375 adult tickets and 1,125 children tickets)
Step-by-step explanation:
Let x be the number of adult tickets sold.
Three times as many children tickets were sold as adults, so 3x is the number of children tickets sold.
Children tickets were three dollars, so 3x children tickets cost 
Adult tickets were seven dollar, so x adult tickets cost 
The school sold $6000 worth of tickets.
Hence,
Answer:
The option "StartFraction 1 Over 3 Superscript 8" is correct
That is 
is correct answer
Therefore ![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2%3D%5Cfrac%7B1%7D%7B3%5E8%7D)
Step-by-step explanation:
Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared
The given expression can be written as
![[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2](https://tex.z-dn.net/?f=%5B%282%5E%7B-2%7D%29%283%5E4%29%5D%5E%7B-3%7D%5Ctimes%20%5B%282%5E%7B-3%7D%29%283%5E2%29%5D%5E2)
To find the simplified form of the given expression :
( using the property 
)
( using the property 
( combining the like powers )
( using the property 
)
( using the property 
)
Therefore
Therefore option "StartFraction 1 Over 3 Superscript 8" is correct
That is is correct answer
