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alexgriva [62]
3 years ago
8

What is the probability of rolling an even number on the first die and an odd number on the second die?

Mathematics
2 answers:
DerKrebs [107]3 years ago
5 0

Answer: 1/4, 25%

Step-by-step explanation: 1/2×1/2=1/4

FinnZ [79.3K]3 years ago
5 0

Answer:

The probability is 25%

Step-by-step explanation:

If you need an even number on your first roll, theres 3 numbers you can get(2, 4 ,6) . So the probability is 3 out of 6(50%).

If you need an odd number on your second roll, there's also 3 numbers you can get(1, 3, 5). So the probability is 3 out of 6(50%).

0.50 times 0.50 = 0.25

So your answer is 25%

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Binomial theorem Expand (5 - y)3
Snowcat [4.5K]

Answer:

(5 - y) ^3 = 125 - 75y + 15y^2 - y^3

Step-by-step explanation:

Binomial expression

1

1. 1

1. 2. 1

1. 3. 3. 1 --------power of 3

( 5 - y) ^3

( 5 - y) (5 - y) (5 - y)

( a + b) ^3 = a^3 + 3a^2b + 3ab^2 + b^3

a = 5

b = -y

( 5 - y) ^2 = ( 5 - y) (5 - y)

= 5( 5 - y) - y(5 - y)

= 25 - 5y - 5y + y^2

=(25-10y+y^2)

( 25 - 10y + y^2)( 5 - y)

= 5(25 - 10y + y^2) - y( 25 - 10y + y^2)

= 125 - 50y + 5y^2 - 25y + 10y^2 - y^3

Collect the like terms

= 125 - 50y - 25y + 5y^2 + 10y^2 - y^3

= 125 - 75y + 15y^2 - y^3

7 0
3 years ago
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jolli1 [7]

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The answer for this question would be
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(x^2-1)(4x^3-3x^2+5)
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Step-by-step explanation:

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