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alexgriva [62]
3 years ago
8

What is the probability of rolling an even number on the first die and an odd number on the second die?

Mathematics
2 answers:
DerKrebs [107]3 years ago
5 0

Answer: 1/4, 25%

Step-by-step explanation: 1/2×1/2=1/4

FinnZ [79.3K]3 years ago
5 0

Answer:

The probability is 25%

Step-by-step explanation:

If you need an even number on your first roll, theres 3 numbers you can get(2, 4 ,6) . So the probability is 3 out of 6(50%).

If you need an odd number on your second roll, there's also 3 numbers you can get(1, 3, 5). So the probability is 3 out of 6(50%).

0.50 times 0.50 = 0.25

So your answer is 25%

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3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20-%2030%20%3D%202%28x%20-%2097%29" id="TexFormula1" title=" - 30 = 2(x - 97)" alt=" - 30 = 2
Korolek [52]
Hey there! 

In order to find out the answer to this question, we can distribute 

-30 = 2(x - 97) \\ \\ \\ 2(x) = 2x \\ \\ 2(97) = 197

Flip your problem around! 

2x - 194 = -30

Add by 194 on each of your sides 

Like:  2x - 194 + 194 \\ \\ \\ -30 + 194

Cancel out: -194 + 194  because they would give you the outcome of 0

Keep: -30 + 194 [/tex] because that'll give you: [tex]164

Your problem becomes: 2x = 164

Now, we have to divide by 2 on each of the sides

Like: \frac{2x}{2}  =  \frac{164}{2}

Cancel: \frac{2x}{2} because it will give you a outcome of 1

Keep: \frac{164}{2} because this will give you your answer

Answer: x = 82

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)
7 0
3 years ago
Which property was used to simplify the expression?<br><br> (y^5)^2 = y^10
gayaneshka [121]
<span>(y^5)^2 = y^10

This is power of a power property</span>
3 0
3 years ago
Read 2 more answers
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