here,
2x-6y= -12
2(x-3y)= -12
x-3y = -6...........eq1
x+2y=14............eq2
we can subtract the above two given equations
we get,
___________
so,
y=4
now to find the value of x we have to substitute the value of y in any of the above two equations, I choose eq2
we get,
Answer:
The amount in the first account is $5,700
The amount in the second account is $1,300
Step-by-step explanation:
Let the mount invested in the first account be and the one invested in the second account be
.
Then the total principal is ---->(1)
The interest in the first account is
The interest in the first account is
The total interest for the year is 262.00.
This implies that:
---->(2)
We solve the two equations simultaneously to get:
and