Answer:
No, the graph fails the vertical line test
Step-by-step explanation:
To determine if the graph is a function, we can use the vertical line test.
Use a vertical line, if the vertical passes through two or more points, the graph is not a function
Looking at the y axis ( which is a vertical line), it passes through two points
This means the graph is not a function
No, the graph fails the vertical line test
Answer:
a) is A b) is D c) is D d) is 2 e) is At lunch time, Benjamin often borrows money from his friends to buy snacks in the school cafeteria. Benjamin borrowed $0.75 from his friend Clyde four days last week to buy ice cream bars. How much does he owe Clyde.
( On question " e) " simply just change the five to a four making him borrow 75 cents 4 times. )
Step-by-step explanation:
Answer:
a) -8/9
b) The series is a convergent series
c) 1/17
Step-by-step explanation:
The series a+ar+ar²+ar³⋯ =∑ar^(n−1) is called a geometric series, and r is called the common ratio.
If −1<r<1, the geometric series is convergent and its sum is expressed as ∑ar^(n−1) = a/1-r
a is the first tern of the series.
a) Rewriting the series ∑(-8)^(n−1)/9^n given in the form ∑ar^(n−1) we have;
∑(-8)^(n−1)/9^n
= ∑(-8)^(n−1)/9•(9)^n-1
= ∑1/9 • (-8/9)^(n−1)
From the series gotten, it can be seen in comparison that a = 1/9 and r = -8/9
The common ratio r = -8/9
b) Remember that for the series to be convergent, -1<r<1 i.e r must be less than 1 and since our common ratio which is -8/9 is less than 1, this implies that the series is convergent.
c) Since the sun of the series tends to infinity, we will use the formula for finding the sum to infinity of a geometric series.
S∞ = a/1-r
Given a = 1/9 and r = -8/9
S∞ = (1/9)/1-(-8/9)
S∞ = (1/9)/1+8/9
S∞ = (1/9)/17/9
S∞ = 1/9×9/17
S∞ = 1/17
The sum of the geometric series is 1/17
Given:
Total number of calculators in a box = 10
Defective calculators in the box = 1
To find:
The number of ways in which four calculators be selected and one of the four calculator is defective.
Solution:
We have,
Total calculators = 10
Defective calculators = 1
Then, Non-defective calculator = 10-1 = 9
Out of 4 selected calculators 1 should be defective. So, 3 calculators are selected from 9 non-defective calculators and 1 is selected from the defective calculator.
Therefore, the four calculators can be selected in 84 ways.
The answer is 12c^8/d^2 or answer A
