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user100 [1]
3 years ago
13

a rectangular red sticker has a perimeter of 20 millimeters . it's area is 21 square millimeters . what are the dimensions of th

e sticker?
Mathematics
1 answer:
Delvig [45]3 years ago
6 0

Answer:

the stick is a 7 by 3

Step-by-step explanation:

7+3+7+3 adds to 20 which would be the perimeter and the area is just length times width so 7 times 3.

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N + 1 - 3N = 9 - N (IN A TEST)
rjkz [21]

Answer:

N= -8

Step-by-step explanation:

a

8 0
2 years ago
Read 2 more answers
consider the triangles shown below. which of the following relationship is needed to prove that ABD ...
Brrunno [24]

A. is the answer.

the 2 triangls have AD = AC

and AB as a common side. therefore the triangls are congruent.

5 0
3 years ago
Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
Can somebody answer these 2 questions
AnnZ [28]

Answer:

2. 12.08

3. 7.74

Step-by-step explanation:

a squared + b squared = c squared

2. 5 squared = 25, 11 squared = 121, 25 + 121 = 146, the squre root of 146 is 12.08

3.19 squared = 361, 421 - 361 = 60 60 squared = 7.74

3 0
3 years ago
Read 2 more answers
This is a tough one :/<br> If f(x) = -x + 7 and g(x) = radical of x– 3,<br> what is (f º g)(4)
Jlenok [28]

Answer:

6

Step-by-step explanation:

To solve, first plug in 4 as your x value for your g(x) equation.

g(4)=\sqrt{4-3} \\g(4)=\sqrt{1} \\g(4)=1

Next, plug in the value of g(4) into your f(x) equation for x.

f(1)=-1+7\\f(1)=6

6 0
3 years ago
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