Wazi has sixty three 5 $ bills he takes the 5 $ bills to bank to exchange for 20$ how many 20$ bills does Wes I get

Anit [1.1K]

Hi!

Your answer is 52.

To start off, let's start with some facts that will help us solve this:

Supplementary angles are two angles whose angle measures add up to 180 degrees. You can know that they are supplementary because they can be connected by a straight line.

Triangles (all of them) have angles that add up to 180 degrees.

We can start by using supplementary angles to solve. See where the angle of 67 degrees is? The one to the right of it is supplementary to it since they are on a straight line. That means their sum adds up to 180 degrees:

$67 +?=180$

$?=113$

That angle is 113 degrees.

Now, we have 2 out of 3 angles in the triangle. Since we know that triangles' angles add up to 180 degrees, we can make an equation:

$15+113+x=180$

$128+x=180$

$x=52$

Therefore, x is equal to 52.

7 0

2 years ago

How would I go about solving 12,15,18 thanks

grigory [225]

For 12, you would do 90=4x+42, and 48=4x, and x=12
for 15, you would do 90=8x+66, and 24=8x, and x=3
for 18, you would do 90=3x+57, and 33=3x, and x=11

3 0

3 years ago

the line joining A(a, 3) to B(2 -3) is perpendicular to the line joining C(10,1) to B. The value of a is?

RideAnS [48]

Well, first off, let's find what is the slope of BC

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
B&({{ 2}}\quad ,&{{ -3}})\quad 
% (c,d)
C&({{ 10}}\quad ,&{{ 1}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{1-(-3)}{10-2}\implies \cfrac{1+3}{10-2}
\\\\\\
\cfrac{4}{8}\implies \cfrac{1}{2}$

now, a line perpendicular to that one, will have a negative reciprocal slope, thus

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{1}{2}\\\\
slope=\cfrac{1}{{{ 2}}}\qquad negative\implies -\cfrac{1}{{{ 2}}}\qquad reciprocal\implies - \cfrac{{{ 2}}}{1}\implies \boxed{-2}$

now, we know the slope "m" of AB is -2 then, thus

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ a}}\quad ,&{{ 3}})\quad 
% (c,d)
B&({{ 2}}\quad ,&{{ -3}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-3-3}{2-a}=\boxed{-2}
\\\\\\
\cfrac{-6}{2-a}=-2\implies -6=-4+2a\implies -2=2a\implies \cfrac{-2}{2}=a
\\\\\\
-1=a$

6 0

3 years ago

When compared with the independent variable, how many of the graphs represent a linear relationship?

strojnjashka [21]

Since a slope differe, this is not linear relationship. Simply, if you connect all points on the graph, they will not lie on the same line. Two next graphs represent the linear relationships, so they represent the linear relationship.

8 0

2 years ago

Ft=50,000(0.47)^t expontional growth

jonny [76]

Answer:

Ok

Step-by-step explanation:

5 0

3 years ago