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snow_lady [41]
3 years ago
9

21 less than a number, multiplied by 4, results in 108.Find the value of the unknown number.

Mathematics
1 answer:
Anni [7]3 years ago
6 0

21 - 4x = 108

<em><u>Subtract 21 from both sides</u></em>

-4x = 87

<em><u>Divide both sides by -4</u></em>

x = -21.75

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A number r is no less than −1.5 and fewer than 9.5
melisa1 [442]

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Step-by-step explanation:


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3 years ago
The rubber playground mulch is sold in packages that cover 300 square feet each. what expression represents the number of packag
tino4ka555 [31]

The expression represents the number of packages of mulch that will be needed to cover both rounded ends is 600/x

<h3>How to determine the expression represents the number of packages of mulch that will be needed to cover both rounded ends?</h3>

The given parameters are:

Area covered = 300 square feet

Number of ends  = 2

So, the total surface area is:

Total surface area = Area covered * Number of ends  

This gives

Total surface area = 300 * 2

Total surface area = 600 square feet

Let the area covered by each package of mulch be x.

So, the number of mulch is

Number = Area covered/area covered by each

This gives

Number = 600/x

Hence, the expression represents the number of packages of mulch that will be needed to cover both rounded ends is 600/x

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6 0
1 year ago
Acellus
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Answer:

24 in

Step-by-step explanation:

i donk know

its a guess

6 0
3 years ago
If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)
sweet-ann [11.9K]

Answer:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

Step-by-step explanation:

Given

tan\theta = 3

Required

Find

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)

Calculate tan(\theta + \pi) \ and\ tan(\theta+2\pi)

Using tan rule

tan(\theta + \pi)  = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}

So:

tan(\theta + \pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + \pi)  = \frac{tan\theta}{1 }

tan(\theta + \pi)  = \tan\theta

tan(\theta+2\pi)

tan(\theta + 2\pi)  = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}

tan(\theta + 2\pi)  = \frac{tan\theta + 0}{1 - tan\theta *0}

tan(\theta + 2\pi)  = \tan\theta'

'So:

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = tan\theta +tan\theta +tan\theta

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3

tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9

4 0
2 years ago
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