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3 years ago

The measure of arc EF is —

Mathematics

2 answers:

Dimas [21]3 years ago

7 0

30 plus EF = 180

Ef = 150

circumscribed angle plus the central angle is 180

Marianna [84]3 years ago

5 0

To have a second opinion, ^ he is correct

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3 years ago

Green

Anon25 [30]

Answer:

Independent events

Step-by-step explanation:

They are independent events because by "lands on yellow" and "lands on green", we're assuming that we're doing something like spinning a spinner, because then we're not taking anything and not replacing it. When we're replacing something, then that's an independent event, and by spinning a spinner once, for Event A, and again for Event B, then we're already replacing everything.

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3 years ago

Una empresa embotelladora de gaseosas lanzará su propia bebida "Delicia" de un litro a un costo variable de S/ 2.50 por unidad,

KIM [24]

Por la ecuación de utilidad, necesitamos una producción de 7,667 botellas de un litro de capacidad para obtener un total de utilidades de S/ 30.000.

<h3>¿Cómo determinar las utilidades por la venta de bebidas gaseosas?</h3>

Las utilidades (U') se obtienen de sustraer los costes de producción (Cp) a las utilidades <em>netas</em> (U). Los costes de producción (Cp) son la suma de costes <em>variables</em> (C') y costes <em>fijos </em>(C). y la utilidades <em>netas</em> proceden de la venta de botellas. En consecuencia, tenemos la siguiente expresión:

U' = U - Cp

U' = U - C' - C

A continuación, desarrollamos y resolvemos la ecuación resultante:

30000 = 4.50 · x - 2.50 · x - 18500

1.50 · x = 11500

x = 7667

Por la ecuación de utilidad, necesitamos una producción de 7,667 botellas de un litro de capacidad para obtener un total de utilidades de S/ 30.000.

Para saber sobre utilidades: brainly.com/question/16933668

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2 years ago

The line $y = 3$ intersects the graph of $y = 4x^2 + x - 1$ at the points $A$ and $B$. The distance between $A$ and $B$ can be w

raketka [301]

Answer:

Step-by-step explanation:

Let's find the points $A$ and $B$ .

We know that the $y$ -coordinates of both are $3$ .

So let's first solve:

$3=4x^2+x-1$

Subtract 3 on both sides:

$0=4x^2+x-1-3$

Simplify:

$0=4x^2+x-4$

I'm going to use the quadratic formula, $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , to solve.

We must first compare to the quadratic equation, $ax^2+bx+c=0$ .

$a=4$

$b=1$

$c=-4$

$\frac{-1 \pm \sqrt{1^2-4(4)(-4)}}{2(4)}$

$\frac{-1 \pm \sqrt{1+64}}{8}$

$\frac{-1 \pm \sqrt{65}}{8}$

Since the distance between the points $A$ and $B$ is horizontal. We know this because they share the same $y-coordinate$ .This means we just need to find the positive difference between the $x$ -values we found for the points of $A$ and $B$ .