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kap26 [50]
4 years ago
10

In fifth grade at lenape elemantary school,there are 4/7 as many girls as there are boys .There are 66 students in fifth grade.H

ow many students are girls?
Mathematics
1 answer:
Strike441 [17]4 years ago
8 0

Answer: there are 24 girls.

Step-by-step explanation:

Let x represent the number of boys in fifth grade at lenape elemantary school.

In fifth grade at lenape elemantary school,there are 4/7 as many girls as there are boys. This means that the number of girls in the school would be

4/7 × x = 4x/7

There are 66 students in fifth grade. This means that

x + 4x/7 = 66

Cross multiplying by 7, it becomes

7x + 4x = 462

11x = 462

x = 462/11

x = 42

The number of girls would be

66 - 42 = 24

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max2010maxim [7]

Answer:

Step-by-step explanation:

To answer this question we should analyze both functions :

  • the intercepts with the x-axis are the numbers when a function f(x)=0

here we must solve both equations :

  1. x²=0
  2. x²+2=0

the first one is obvious x=0 the scond is more interesting :

x²+2=0⇔x²=-2 wich is impossible since x²≥0 unless we use complex numbers .

So we notice thatf has one intercept.

we added 2 to f to get g but no real intercepts

5 0
4 years ago
There were 10 baked goods in a basket. four of them were sold. write a fraction to show the part of the baked goods that were no
Zina [86]
<span>The fraction of baked goods not sold is 6/10. The numerator is the number of left over baked goods (10-4 -6) and the denominator is the total loaves of bread (10). An equivalent fraction is 12/20. This was obtained by multiplying the original fraction by two (6 x2 = 12 and 10 x2 =20).</span>
5 0
3 years ago
On a given Monday, the probability of rain is 0.72, the probability that the maximum temperature for the day will exceed 75°F is
elena55 [62]
We know that
the addition rule states that
 P(A or B) = P(A) + P(B) − P(A and B)
in this problem
P(A)=0.72
P(B)=0.84
P(A and B)=0.64
so
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the answer is
0.92 (92%)

4 0
3 years ago
Read 2 more answers
Last question was inncorrectly typed:1.A sample of students who has taken a calculus test has a mean =78.2, mode =67, median 67.
vampirchik [111]

Answer:

(A) The data set of the sample of students who has taken a calculus test is right skewed.

(B) The average of female students in the class is 66.

Step-by-step explanation:

(A)

For a left skewed distribution the Mean < Median < Mode.

For a right skewed distribution the Mean > Median > Mode.

For a symmetric distribution the Mean = Median = Mode.

Given: Mean = 78.2, Median = 67 and Mode = 67

In this case the mean of the data is more than the median and mode.

Mean = 78.2>Median = Mode = 67

Thus, the data set of the sample of students who has taken a calculus test is right skewed.

(B)

Total number of student (n) = 35

Combined average (\mu_{c}) = 70

Number of male student (n_{M}) = 20

Average of male students (\mu_{M}) = 73

Number of female student (n_{F}) = 15

Average of female students = \mu_{F}

The formula to compute the combined average is:

\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}

Compute the value of \mu_{F} as follows:

\mu_{c}=\frac{n_{M}\mu_{M}+n_{F}\mu_{F}}{n_{M}+n_{F}}\\70=\frac{(20\times73)+(15\times\mu_{F})}{20+15}\\ 70\times35=1460+(15\times\mu_{F})\\\mu_{F}=\frac{2450-1460}{15} \\=66

Thus, the average of female students in the class is 66.

8 0
4 years ago
Brandon has a jar of quarters and dimes with a total value of $7.85. The number of quarters is 7 less than twice the number of d
neonofarm [45]

Answer:

dimes=8

quarters=12

Step-by-step explanation:

the total value 380 cents

8 0
3 years ago
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