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geniusboy [140]
3 years ago
15

A point is randomly chosen on a map of North America. Describe the probability of the point being in each location: North Americ

a: New York City: Europe:
Mathematics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

We know that the map is of North America:

The probabilities are:

1) North America:

As the map is a map of North America, you can point at any part of the map and you will be pointing at North America, so the probability is p = 1

or 100% in percentage form.

2) New York City.

Here we can think this as:

The map of North America is an extension of area, and New Yorck City has a given area.

As larger is the area of the city, more probable to being randomly choosen, so to find the exact probability we need to find the quotient between the area of New York City and the total area of North America:

New York City = 730km^2

North America = 24,709,000 km^2

So the probability of randomly pointing at New York City is:

P = ( 730km^2)/(24,709,000 km^2) = 3x10^-5 or 0.003%

3) Europe:

As this is a map of Noth America, you can not randomly point at Europe in it (Europe is other continent).

So the probaility is 0 or 0%.

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aliya0001 [1]

First we'll substitute \frac{dy}{dx} with y'

y'=\frac{4x}{y}

Then we can separate this.

yy'=4x

Then we'll solve this.

yy'=4x: \frac{y^2}{2}=2x^2+c_1

\frac{y^2}{2}=2x^2-6

y=2\sqrt{x^2-3},y=-2\sqrt{x^2-3}

Then we'll plug in to find the extraneous solutions (if any)

y=-2\sqrt{x^2-3}

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3 years ago
Train A leaves Westtown and travels at 50 mph toward Smithville, 330 miles away. At the same time, Train B leaves Smithville and
lianna [129]
The answer to this question is that the trains will meet after 3 hours. We can work this out by considering that is the closing speed of the two trains is (50+60=)110 miles per hour, then this must mean that the combined distance that the trains need to travel before they meet is 330 miles. If the time that is taken to travel 330 miles at 110 miles per hour, then you simply need to divide 330/110 to find your answer - 3 hours.
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What's the like terms for ; 7(d-1) + 2 , and the answer being simplified?
Lyrx [107]

Answer: Like terms are -7 and 2. Simplified version would be 7d-5.

Step-by-step explanation:

first you would distribute, so it would be 7(d-1)+2 = 7d-7+2. Combine like terms. The only like terms here are -7 and 2, so just basically subtract -7 from 2 and you would get -5. you can't do anything with 7d because there is no like term for it.

7 0
3 years ago
Thank you for anyone who knows this
katen-ka-za [31]

Answer:  

  • Part (a) Vertex = (-3, -1)
  • Part (b) Vertex = (4, 5)
  • Part (c) function 2; max value = 5

=====================================================

Explanations:

Part (a)

In this case, the vertex is the highest point, so the vertex of function 1 is (-3, -1)

If the parabola was flipped so that it opened upward, instead of downward, then the vertex would be the lowest point.

----------------------------

Part (b)

We could graph this function to see where the highest or lowest point is, but there's another way we could find the vertex using algebra.

The given equation is in the form y = ax^2 + bx + c where in this case

  • a = -2
  • b = 16
  • c = -27

The a and b values are plugged into the formula below to get

h = -b/(2a)

h = -16/(2*(-2))

h = -16/(-4)

h = 4

This is the x coordinate the vertex since the vertex is (h,k)

To find k, we plug that value of h into the original function to find its corresponding y value.

y = -2x^2 + 16x - 27

y = -2(4)^2 + 16(4) - 27

y = -2(16) + 16(4) - 27

y = -32 + 64 - 27

y = 5

We found that h = 4 leads to k = 5. The vertex is (h,k) = (4, 5)

----------------------------

Part (c)

We'll compare the y values of each vertex

  • Function 1 has a vertex of (-3, 1)
  • Function 2 has a vertex of (4, 5)

The vertex with the larger y value is the winner, so that would be function 2. This parabola reaches a higher peak compared to the other curve.

The max value here is y = 5. In other words, it's the maximum output the function can produce.

If you graphed functions 1 and 2 together on the same xy grid (see below), you'll see that the curve for function 2 reaches a higher peak.

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Identify a like that the rectangle could be reflected over to result in a rectangle that has the same vertices as the original.
stealth61 [152]

Answer: x=6

Step-by-step explanation: move 6 spaces and you get the same vertices

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