(6x^2+5x+1)/(3x^2+4x+1)
= (3x+1)(2x+1)/(3x+1)(x+1)
= (2x+1)/(x+1)
Answer:
y = 5x -12
Step-by-step explanation:
point-slope form:
y - y1 = m(x-x1)
m= slope
m= (y2-y1)/ (x2-x1)
we have (4, 8) and (2,-2)
x1 = 4 y1= 8
x2= 2 y2= -2
m=( -2-8) / (2- 4)
m= -10/ -2
m= 5
so we have:
y - 8 = 5(x-4)
y - 8= 5x -20
y= 5x -20 +8
y = 5x -12
7 2/3 - 5 5/8 = 7 16/24 - 5 15/24 = 2 1/24
<u>Answer:
</u>
Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
<u>
Solution:
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Need to find the five terms of the sequence.
Given recursive rule is f(x) = f(x-1) -7
Substituting x = 2 , f(2) = f(2-1)-7
= f(2) = f(1) – 7 ------(1)
Also given that f(2) = 12.
On substituting the given value of f(2) in eq (1) we get
12 = f(1) – 7
f(1) = 12 + 7 = 19
Using given recursive rule and given value of f(2) calculating f(3)
Substituting x = 3 ,
f(3) = f(3-1) – 7
= f(2) – 7
= 12 – 7
= 5
Using given recursive rule and calculated value of f(3) calculating f(4)
Substituting x = 4,
f(4) = f(4-1) – 7
= f(3) – 7
= 5– 7
= -2
Using given recursive rule and calculated value of f(4) calculating f(5)
Substituting x = 5,
f(5) = f(5-1) – 7
= f(4) – 7
= -2– 7
= -9
Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .
