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PilotLPTM [1.2K]
3 years ago
12

A scale drawing of a field is shown below. The drawing uses a scale of 1 in. = 14 ft. What is the area of the actual field?

Mathematics
1 answer:
svp [43]3 years ago
3 0

Answer:

D. 4,704 ft²

Step-by-step explanation:

Giving a scale of 1 in. = 14 ft, to find the actual area of the field represented by the triangular drawing above, convert the length of the base and height to the actual lengths of the field using the scale.

Height of drawing = 8 in.

Actual height = 8*14 = 112 ft

Base of drawing = 6 in.

Actual base = 6*14 = 84 ft

Area of the field = area of ∆

Area = ½*base*height

Area = ½*84*112

Area = 4,704 ft²

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STEP 3: Vertical stretch.

If we transform

\sqrt{x+2}\mapsto 3\sqrt{x+2}

We're performing a change in the form of

f(x)\mapsto kf(x)

This kind of changes result in a vertical stretch with scale factor k. If k is negative, the function is also reflected across the x axis. In this case, k=3, so the original graph is stretched vertically, with scale factor 3.

STEP 3: Vertical translation.

If we transform

3\sqrt{x+2}\mapsto 3\sqrt{x+2}-4

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