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3 years ago

How can we tell if a fraction is less that greater than or equal to 1?

2 answers:

Klio2033 [76]3 years ago

8 0

If the number on top is bigger than the number on the bottom then it is more than one. if the number on the top is smaller then the number on the bottom then it is less than one. if the bottom and top number are the same then it is 1.

Stels [109]3 years ago

5 0

If the numerator is less than the denominator, then the fraction is less than 1.
E.g.: 3/4 < 1, because 3 < 4.

If the numerator is larger than the denominator, then the fraction is greater than 1.
E.g.: 5/4 > 1, because 5 > 4.

If the numerator is equal to the denominator, then the fraction is equal to 1.
E.g.: 9/9= 1, because 9=9.

Hope this helps~

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Which of the following expressions are equivalent

Ber [7]

It’s 2 and 3 bc 6a+12 and then 3(2a+4) and you need to distribute for that so 3 times 2a equals 6a and 3 times 4 equals 12 so you get 6a+12

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3 years ago

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Dennis_Churaev [7]

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3 years ago

Calculate the total area of the shaded region.

LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

$\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}$

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

$\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill$

$\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}$

7 0

2 years ago

Please help me on this!!<br> 5n+17≥n–3≥–15+5n

DENIUS [597]

Answer:

-5 ≤ n ≤ 3

Step-by-step explanation:

Firstly we solve the equation two at a time;

5n + 17 ≥ n - 3

5n - n ≥ -3 - 17

4n ≥ -20

n ≥ -5

-5 ≤ n

n - 3 ≥ -15 + 5n

n - 5n ≥ -15 + 3

-4n ≥ -12

-n ≥ -3

n ≤ 3

Therefore,

5n+17 ≥ n–3 ≥ –15+5n, becomes

-5 ≤ n ≤ 3

6 0

3 years ago

If 3:y=18:24 find y.

VashaNatasha [74]

y = 4

Explanation: $\begin{gathered} 3\text{ : y = 18 : 24} \\ 3\colon y\text{ = }\frac{3}{y} \\ 18\colon24\text{ = }\frac{18}{24} \end{gathered}$ $\begin{gathered} \frac{3}{y}\text{ = }\frac{18}{24} \\ \text{cross mult}iply\colon \\ 3(24)\text{ = y(18)} \\ \text{divide both sides by 18:} \\ \frac{3(24)}{18}\text{ = }\frac{18y}{18} \end{gathered}$ $\begin{gathered} y\text{ = }\frac{24}{6} \\ y\text{ = 4} \end{gathered}$

7 0

1 year ago