According to the identity if a+b+c=0
then a3+b3+c3=3abc
a3+b3+c3/abc=3
a2*a/bc*a+b2*b/ca*b+c2*c/ab*c=3
cancel a,b,c in all the fraction then you get
<span>a²/bc+b²/ca+c²/ab=3.
</span>hence proved
Divide 7 by 8 then multiply what you get by 100.
Answer:
exercising
Step-by-step explanation:
Answer:
I think she is correct
Step-by-step explanation:
in not. sure so dont take my word for it