The diagram shows how data demand increases with data variety and complexity.

An ideal gas is confined within a closed cylinder at a pressure of 2.026 × 105 Pa by a piston. The piston moves until the volume

Elis [28]

Answer:

The final pressure of the gas when its temperature returns to its initial value $1.8234\times 10^6$ Pa.

Step-by-step explanation:

Given : An ideal gas is confined within a closed cylinder at a pressure of $2.026\times 10^5$ Pa by a piston. The piston moves until the volume of the gas is reduced to one-ninth of the initial volume.

To find : What is the final pressure of the gas when its temperature returns to its initial value?

Solution :

Since the temperature is constant .

The relation between P and V is given by,

$P_1\times V_1 = P_2\times V_2$

$\frac{P_1}{P_2}=\frac{V_2}{V_1}$ ....(1)

The piston moves until the volume of the gas is reduced to one-ninth of the initial volume i.e. $V_2=\frac{V_1}{9}$

or $\frac{V_2}{V_1}=\frac{1}{9}$

$P_1=2.026\times 10^5$

Substitute in equation (1),

$\frac{2.026\times 10^5}{P_2}=\frac{1}{9}$

$P_2=9\times 2.026\times 10^5$

$P_2=18.234\times 10^5$

$P_2=1.8234\times 10^6$

The final pressure of the gas when its temperature returns to its initial value $1.8234\times 10^6$ Pa.

5 0

3 years ago

Jasmine and her brother Nat are saving to buy a digital camera that costs $135. Jasmine earns $15 per week for babysitting and s

zepelin [54]

Answer:

7 weeks

Step-by-step explanation:

Jasmine=$10

Nat=$11

10+11=$22 each week

135/22=6.14

at least 7 weeks

3 0

3 years ago

Given:

rusak2 [61]

Answer:the answer is c

Step-by-step explanation:

6 0

3 years ago

Please solve this quick 8n+7=31

emmasim [6.3K]

Hello there!

To find the value of n, work to isolate it from all other terms in the equation.

8n+7=31 - Start by subtracting 7 from both sides. 8n + 7 - 7 = 31 - 7

8n = 24 Next, divide both sides by 8 to finish isolating n. 8n÷8 = 24÷8

n = 3

This is your final answer.

I hope this was helpful and have a great rest of your day!

:)

6 0

3 years ago

Read 2 more answers

Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg

Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) Optimal solution: 40.000 units of R and 10.000 of PC = $17.000

c) Slack variables: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) Binding Constaints:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.

3 0

3 years ago