To solve for the surface area of the pyramid, we make use
of the formula:
A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))
where,
l and w are the base of the pyramid = 100 mm
h is the height of the pyramid = 75 mm
Substituting the given values into the equation:
A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100
/ 2)^2 + 75^2))
A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)
A = 20,148.90 mm^2
Therefore the surface area of the pyramid is about 20,149
mm^2.
127.5° is the answer please mark brainliest
The correct answer is 20 because if you solve A=hbb 1=5 8 2=20 Hope this helps! ;D
Answer:
How do you describe the sequence of transformations?
Image result for Describe a sequence of transformations that takes trapezoid A to trapezoid B
When two or more transformations are combined to form a new transformation, the result is called a sequence of transformations, or a composition of transformations. Remember, that in a composition, one transformation produces an image upon which the other transformation is then performed.
Step-by-step explanation:
N-2= 1/16
⇒ n= 1/16+ 2 (inverse operation)
⇒ n= 2+ 1/16
⇒ n= 2 1/16
Final answer: n= 2 1/16.
