3-2*4*4 what’s the answer

The formula a=6s^2 will calculate the surface area of a cube. suppose you have a cube that has a surface area of 216 square inch

lawyer [7]

216 = 6s^2

can be solved in the following manner.

216/6=s^2
36 = s^2
sqrt(36) = s

flip for better overview

s = 6

the length of each side is 6 inches. :)

4 0

3 years ago

Kari's paper cup holds 6 fluid ounces. If one ounce is equivalent to 29.6 milliliters, how many milliliters does her paper cup h

Degger [83]

Answer:

Equivalent measurements: teaspoon, ounce, pint, pound

You will find a table of equivalent measurements in the back of many cookbooks:

1 tablespoon = 3 teaspoons

1 cup = 16 tablespoon = 8 ounces

1/4 cup = 4 tablespoons

1/3 cup = 5 tablespoons plus 1 teaspoon

1 pint = 2 cups = 16 ounces

1 quart = 4 cups (2 pints) = 32 ounces

1 gallon = 4 quarts

1 pound = 16 ounces

1/2 pound = 8 ounces

1/4 pound = 4 ounces

Note that a pint is 16 ounces of volume, while a pound is 16 ounces of weight. The popular rhyme "A pint's a pound, the world around" can help you remember this, but keep in mind that they're not really equivalent.

Doubling a recipe can be easy (just put in two of each measurement), but what if you need to divide a recipe in half? Here are some measurements that may help:

Measurement 1/2 Measurement

1/8 teaspoon just a dash

1 tablespoon 1 1/2 teaspoons

1/4 cup 2 tablespoons

1/3 cup 2 tablespoons + 2 teaspoons

3/4 cup 6 tablespoons

Step-by-step explanation:

7 0

3 years ago

The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When

atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

$A=w\ell$

Where w is the width and l is the length.

We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to t, where w and l are both functions of t:

$\displaystyle \frac{dA}{dt}=\frac{d}{dt}\left[w\ell]$