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luda_lava [24]
4 years ago
13

Nancy wrote the greatest number that can be made using each of these digits exactly once. 5,3,4,9,8,1. Part A what was Nancy's n

umber? how do you know this is the greatest possible number for this digits?.Part B What is the least number that can be made using each digit exactly once? explain why the value of the 4 is greater than the value of the 5
Mathematics
2 answers:
mihalych1998 [28]4 years ago
5 0
Part A: Nancy's number was 985,431. I know this because when you arrange these numbers from greatest to least you get the answer provided. Part B: The least number that can be made is 134,589. The value of 4 is greater than 5 because it is in the thousands place. Please mark my answer as brainliest
Tatiana [17]4 years ago
4 0

Answer:

Part A: 985,431

Part B: 134,589

Step-by-step explanation:

In order to solve part A, you just have to take the greatest digit and place it in the far left place of the number, and continue to the next greatest digit, placing it to the right of the last number, this will create a decreasing ladder of digits among the decreasing values of the number, this way Thousands-hundreds-tens-, so you will have the greatest number possible in the highest valued place possible.

To calculate the lowest number possible you just have to do the process for the greatest but instead of taking the highest digit possible, you use the lowest one, this way you will have the lowest number in the highest value position.

The value of 4 is greater than the value of 5 because the 4 represents in the number the thousands, and the 5 in the number represents the hundreds.

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irakobra [83]

Answer:

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Step-by-step explanation:

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4 years ago
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AleksAgata [21]

Answer:

3

Step-by-step explanation:

First set up your data in order

0,0,0,0,1,1,1,2,2,2,2,3,3

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3 years ago
2. The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability th
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Answer:

0.30

Step-by-step explanation:

Probability of stopping at first signal = 0.36 ;

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Probability of stopping at second signal = 0.54;

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P(x U y) = 0.6

Stopping at both signals :

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P(xny) = 0.36 + 0.54 - 0.6

P(xny) = 0.3

Stopping at x but not y

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P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24

Probability of stopping at exactly 1 signal :

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3 years ago
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sashaice [31]

Answer:160

Step-by-step explanation:

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3 years ago
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