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3 years ago

10

Solve the Equation. 20x + 12 ≥ 14x + 30 A. x ≥ 7 B. x ≤ 7 C. x ≥ 3 D. x ≤ 3

2 answers:

Tamiku [17]3 years ago

8 0

Answer:

x≥3

Step-by-step explanation:

Treat the ≥ symbol like it is an equals sign. First, subtract 14x from each side to get 6x+12≥30. Then, Subtract 12 from each side to get 6x≥18. I will let you solve the rest :)

Zarrin [17]3 years ago

8 0

Answer:

$\huge\boxed{C.\ x\geq3}$

Step-by-step explanation:

$20x+12\geq14x+30\qquad\text{subtract 12 from both sides}\\\\20x+12-12\geq14x+30-12\\\\20x\geq14x+18\qquad\text{subtract}\ 14x\ \text{from both sides}\\\\20x-14x\geq14x-14x+18\\\\6x\geq18\qquad\text{divide both sides by 6}\\\\\dfrac{6x}{6}\geq\dfrac{18}{6}\\\\\boxed{x\geq3}$

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