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balandron [24]
3 years ago
10

Solve the Equation. 20x + 12 ≥ 14x + 30 A. x ≥ 7 B. x ≤ 7 C. x ≥ 3 D. x ≤ 3

Mathematics
2 answers:
Tamiku [17]3 years ago
8 0

Answer:

x≥3

Step-by-step explanation:

Treat the ≥ symbol like it is an equals sign. First, subtract 14x from each side to get 6x+12≥30. Then, Subtract 12 from each side to get 6x≥18. I will let you solve the rest :)

Zarrin [17]3 years ago
8 0

Answer:

\huge\boxed{C.\ x\geq3}

Step-by-step explanation:

20x+12\geq14x+30\qquad\text{subtract 12 from both sides}\\\\20x+12-12\geq14x+30-12\\\\20x\geq14x+18\qquad\text{subtract}\ 14x\ \text{from both sides}\\\\20x-14x\geq14x-14x+18\\\\6x\geq18\qquad\text{divide both sides by 6}\\\\\dfrac{6x}{6}\geq\dfrac{18}{6}\\\\\boxed{x\geq3}

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solve your system of equations.

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x=−2y−1

Substitute (−2y−1) for x in x−y=5:

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Read 2 more answers
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