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3 years ago

Carlos has 4/5 of a tank of fuel In his car. he uses 1/10 of a tank per day. How many days will his fuel last?

Mathematics

1 answer:

damaskus [11]3 years ago

8 0

Answer:

8 days

Step-by-step explanation:

4/5= 8/10

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if two events A and B, are independent then which of the following is always true about their possibilities?

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Their possibilities will always be at random.

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The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

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Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

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3 years ago

A rectangular area of land is being sold off in smaller pieces. The total area of the land is 2^15 square miles. The pieces bein

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Total area of the rectangular land = 2^15 sq. miles
= 32768 sq. miles

total area of the pieces being sold = 8^3 sq. miles
= 512 sq. miles

now total no. of pieces = total area of the land / the area of samaller land that's being sold
= 32768 / 512
= 64

so the actual number of pieces is 64

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What is negative 1 and three fifths divided by negative two thirds equals?

Rudik [331]

It's visually better to make it an equation.
-1 3/5 ÷ -2/3

The answer is 39/10.

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Given: M(-4,-1), B(-5,-3) find the midpoint

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$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
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% (c,d)
B&({{ -5}}\quad ,&{{ -3}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
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