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Arada [10]
2 years ago
6

The equation y=2.54x gives the length y in centimeters corresponding to a length x in inches. What is the length in centimeters

of a 1-foot ruler? Help please!!!!!!
Mathematics
1 answer:
bija089 [108]2 years ago
6 0
The equation given in the question is
y = 2.54 x
In this equation, x is in cm and y is in inches
Size of the ruler = 1 foot 
                          = 12 inches.
Putting the value of 12 inches in the equation, we get
y = 2.54x
   = 2.54 * 12
   = 30.48 cm
From the above deduction, we can conclude that the length of the ruler is 30.48 cm. I hope that this is answer that you were looking for and the answer has come to your desired help.
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Answer: 95.64% of the values will be below 212.5 in our set of data.

First, determine the z-score for the expected value of 212.5. The z-score is the number of standard deviations that it is above or below the mean.

(212.5 - 192.3) / 11.8 = 1.71

A score of 212.5 is 1.71 standard deviations above the mean. Now, use a table to find the probability for a z-score of 1.71. The percent is 95.64%.
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PLEASE HELP!!! Trapezoid ABCD was dilated to create trapezoid A'B'C'D'. Which statements are true about the trapezoids? Check al
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Answer:

Option A , B and D are true.

The statement which are true:

The length of side AD is 4 units

The length of side A'D' is 8 units.

The scale factor is, \frac{1}{2}

Step-by-step explanation:

Given in figure trapezoid ABCD;

The coordinates of ABCD are:

A= (-4, 0)

B = (-2, 4)

C = (2,4)

D = (4, 0)

Since, trapezoid ABCD was dilated to create trapezoid A'B'C'D' as shown in figure;

The coordinates of A'B'C'D' are;

A' =(-2, 0)

B'=(-1, 2)

C' = (1, 2)

D' = (2, 0)

First calculate the length of AD

Using Distance formula for any two points i.e,

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Since, A = (-4, 0) and D = (4, 0)

then;

Length of AD =  \sqrt{(4-(-4))^2+(0-0)^2}  = \sqrt{(4+4)^2} =\sqrt{64}=8 units

Therefore, the length of side AD is, 8 units.

Similarly find the length of A'D'.

Where A' = (-2, 0) and D' =(2,0)

Using distance formula:

Length of A'D' = \sqrt{(2-(-2))^2+(0-0)^2} =\sqrt{(2+2)^2}= \sqrt{4^2} = 4

Therefore, the length of side A'D' is, 4 units.

Now, find the slope of CD and C'D'

where C =(2, 4) , D = (4, 0) , C' = (1, 2) and D' =(2,0)

using slope formula for any two points is given by:

Slope = \frac{y_2-y_1}{x_2-x_1}

Slope of CD = \frac{0-4}{4-2} = \frac{-4}{2} = -2

Similarly,

Slope of C'D' = \frac{0-2}{2-1} = \frac{-4}{2} = -2

Since, Sides CD and C'D' have same slope i.e, -2

Scale factor(k) states that every coordinate of the original figure has been multiplied by the scale factor.

  • If k > 1, then the  image is an enlargement.
  • if 0<k< 1, then the image is a reduction.
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The rule for dilation with scale factor(k) is;

(x, y) \rightarrow (kx , ky)

To find the scale factor:

A = (-4, 0) and A' = (-2, 0)

(-2, 0) \rightarrow (-4k , 0)

On comparing we ghet;

-4k = -2

Divide -4 both sides we get;

k = \frac{1}{2}

∴ The Scale factor is, k = \frac{1}{2}

Since, k < 1 which implies the image is a reduction.

Therefore, the statements which are true regarding about trapezoids are;

The length of side AD is 4 units

The length of side A'D' is 8 units.

The scale factor is, \frac{1}{2}

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