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Anni [7]
3 years ago
5

Simplify completely quantity 2 x squared plus 16 x plus 30 all over quantity 5 x squared plus 13 x minus 6.

Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0
(2x^2 + 16x + 30) / (5x^2 + 13x -6)
Start by factoring the numerator and denominator.
Cancel any like factors.

2(x^2 + 8x + 15)
2(x + 5)(x + 3) / (5x -2)(x + 3
2(x + 5) / (5x - 2)
The third choice
kvasek [131]3 years ago
6 0

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Quantity 2 x squared plus 16 x plus 30 all over quantity 5 x squared plus 13 x minus 6 i.e.

\frac{2x^2+16x+30}{5x^2+13x-6}

We just need to simplify the numerator and denominator :

1) Simplify the numerator by using the Splitting the middle terms:

2x^2+16x+30\\\\=2x^2+10x+6x+30\\\\=2x(x+5)+6(x+5)\\\\=(2x+6)(x+5)\\\\=2(x+3)(x+5)

2) Simplify the denominator by using the Splitting the middle terms:

5x^2+13x-6\\\\=5x^2+15x-2x-6\\\\=5x(x+3)-2(x+3)\\\\=(5x-2)(x+3)

Now, we use the both results in the expression:

\frac{2(x+3)(x+5)}{(5x-2)(x+3)}\\\\=\frac{2(x+5)}{5x-2}

So, 2 open parentheses x plus 5 close parentheses over quantity 5 x minus 2.

Hence, Third option is correct.


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