Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a ![Pr = \frac{2}{110}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B2%7D%7B110%7D)
b ![Pr = \frac{72}{110}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B72%7D%7B110%7D)
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
![Pr = P(D) * P(D)](https://tex.z-dn.net/?f=Pr%20%3D%20P%28D%29%20%2A%20P%28D%29)
![Pr = \frac{2}{11} * \frac{2-1}{11-1}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B2%7D%7B11%7D%20%2A%20%5Cfrac%7B2-1%7D%7B11-1%7D)
![Pr = \frac{2}{11} * \frac{1}{10}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B2%7D%7B11%7D%20%2A%20%5Cfrac%7B1%7D%7B10%7D)
![Pr = \frac{2}{110}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B2%7D%7B110%7D)
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
![P(D') = \frac{9}{11}](https://tex.z-dn.net/?f=P%28D%27%29%20%3D%20%5Cfrac%7B9%7D%7B11%7D)
For two selections, the probability that all are not defective is:
![Pr = P(D') * P(D')](https://tex.z-dn.net/?f=Pr%20%3D%20P%28D%27%29%20%2A%20P%28D%27%29)
![Pr = \frac{9}{11} * \frac{9-1}{11-1}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B9%7D%7B11%7D%20%2A%20%5Cfrac%7B9-1%7D%7B11-1%7D)
![Pr = \frac{9}{11} * \frac{8}{10}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B9%7D%7B11%7D%20%2A%20%5Cfrac%7B8%7D%7B10%7D)
![Pr = \frac{72}{110}](https://tex.z-dn.net/?f=Pr%20%3D%20%5Cfrac%7B72%7D%7B110%7D)
Answer:
since 7 is raised to the power 0 the answer is
a) linear polynomial with zero terms
Answer:
19
Step-by-step explanation:
79÷4=19R3
≈ 19
Answer:
The last one f(x)=(x+2)2+1 because two units to the right is positive and going up is also positive
A linear inequality to represent the algebraic expression is given as 492.46 - x ≥ 500
<h3>Linear Inequality</h3>
Linear inequalities are inequalities that involve at least one linear algebraic expression, that is, a polynomial of degree 1 is compared with another algebraic expression of degree less than or equal to 1.
In this problem, her minimum balance must not decrease beyond $500 or she will pay a fee.
where
The inequality to represent this can be written as
524.96 - 32.50 - x ≥ 500
Simplifying this;
492.46 - x ≥ 500
The linear inequality is 492.46 - x ≥ 500
Learn more on linear inequality here;
brainly.com/question/23093488
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