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julia-pushkina [17]
3 years ago
6

Which expression is equivalent to 6 minus (negative 8)?

Mathematics
2 answers:
Masteriza [31]3 years ago
8 0

Answer:

6 - (-8)

is 6 + 8

Step-by-step explanation:

borishaifa [10]3 years ago
6 0

Answer:

6 - (-8)

Step-by-step explanation:

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What is the difference of the lengths of and ? use the value = 3.14, and round the answer to two decimal places. a. 1.25 units b
natulia [17]

The difference between the length of arc BD and CE is 1.57 units

<h3>Length of an arc</h3>

length of arc = ∅ / 360 × 2πr

where

  • r = radius
  • ∅ = central angle

Therefore,

BD = 45 / 360 × 2 × 3.14 × 6 = 1695.6 / 360 = 4.71 units

CE = 45 / 360 × 2 × 3.14 × 8 = 2260.8 / 360 = 6.28 units

Therefore, the difference between the length of arc BD and CE is as follows:

6.28 - 4.71 = 1.57 units

learn more on length of arc here: brainly.com/question/3984590

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6 0
2 years ago
What is the sum of the number of faces the number of vertices and number of edges
scoray [572]

Answer:

There are 5 faces, 5 vertices, and 8 edges, so all of that together is 18

8 0
3 years ago
Read 2 more answers
Apply the distributive property to create an equivalent expression.<br><br> (1−2g+4h)⋅5
alex41 [277]

Answer:

Step-by-step explanation:

distribute 5 in parenthesis means you multipy each term by 5

5*1-5*2 g+5*4h = 5-10g+20h

5 0
3 years ago
Demand for your tie-dyed T-shirts is given by the formula q = 510 − 90p0.5 where q is the number of T-shirts you can sell each m
telo118 [61]

Answer:

The demand will drop approximately 23 T-shirt per month.

Step-by-step explanation:

Consider the provided formula.

q = 510-90p^{0.5}

You currently sell T-shirts for $15 each and you raise your price by $2 per month,

That means p=$15 and \frac{dp}{dt}=2

We need to find how fast demand will drop.

So differentiate the above function with respect to time.

\frac{dq}{dt} =0-45p^{0.5-1}\frac{dp}{dt}

\frac{dq}{dt} =-45p^{-0.5}\frac{dp}{dt}

Substitute the respective values as shown:

\frac{dq}{dt} =-45(15)^{-0.5}(2)

\frac{dq}{dt} \approx-23.24

Hence, the demand will drop approximately 23 T-shirt per month.

3 0
3 years ago
the height of an object thrown vertically is given by s=-16t^2+100t+200. Height is meter and time is n seconds.
koban [17]

Answer:

456.25m

Step-by-step explanation:

Since the question did not ask for what to find, we can as well look for the maximum height reached by the object

Given the height of an object thrown vertically expressed as;

s=-16t^2+100t+200.

At max height,

dS/dt = 0

-32t+100 = 0

-32t = -100

t = 100/32

t = 3.125s

Get the Max height

s(3.125) = -16(3.125)²+100(3.125)+200

s(3.125) = -156.25+312.5+200

s(3.125) = 456.25m

Hence the maximum height reached by the object is 456.25m

5 0
3 years ago
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