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Yuliya22 [10]
2 years ago
12

What is the angle for the following numbers?

Mathematics
1 answer:
liberstina [14]2 years ago
3 0

Answer:

nooooooooooooooooooooooo se xd

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Find the slope of the line that passes through (4,9) and (1,7)
denis-greek [22]

Answer:

2/3

Step-by-step explanation:

Use the formula for finding gradient.

7 0
3 years ago
Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3
AlexFokin [52]
The ODE is separable, i.e. you can write

\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx

Integrating both sides gives the general solution.

\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx
y=-\ln|\cos x|+C

Given that y\left(\dfrac\pi4\right)=3, we have

3=-\ln\left|\cos\dfrac\pi4\right|+C
3=-\ln\dfrac1{\sqrt2}+C
3-\ln\sqrt2=C


and so the particular solution to the IVP is

y=-\ln|\cos x|+3-\ln\sqrt2
y=3-\ln|\sqrt2\cos x|
4 0
3 years ago
PLZ HELP ASAP WILL MARK BRAINLIEST
RSB [31]

Answer:

72\sqrt{3}

Step-by-step explanation:

The area (A) of a rhombus is calculated as

A = \frac{1}{2} × d₁ × d₂ (d₁ and d₂ are the diagonals )

The diagonals bisect each other at right angles

d₁ = 2 × 6 = 12

Use the tangent ration in the upper left right triangle and the exact value

tan60° = \sqrt{3}

tan60° = \frac{opposite}{adjacent} = \frac{opp}{6} = \sqrt{3} ( multiply both sides by 6 )

opp = 6\sqrt{3} , then

d₂ = 2 × 6\sqrt{3} = 12\sqrt{3}

Thus

A = \frac{1}{2} × 12 × 12\sqrt{3} = 6 × 12\sqrt{3} = 72\sqrt{3}

3 0
2 years ago
SOMEONE HELP ME PLEASE
jenyasd209 [6]

Answer: The median, because the data distribution is skewed to the left

EXPLANATION

Given the box plot with the following parameters: 

Minimum value at 11

First Quartile, Q1 at 22.5

Median at 34.5

Third Quartile, Q3 at 36

Maximum value at 37.5

First, we notice that the data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile

(22.5).

Furthermore, we know that the mean provides a better description of the center when the data distribution is symmetrical while the median provides a better description of the center when the data distribution is skewed.

Therefore, we conclude that for the given box plot, the median will provide a better description of the center because the data distribution is skewed to the left.

4 0
3 years ago
When I checked my bank account this morning I had $4,300. This is a relief
Ivan

Answer:

ahaha that's good

you didn't steal right?

haha jk

lucky you!

3 0
2 years ago
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