solution:
Z1 = 5(cos25˚+isin25˚)
Z2 = 2(cos80˚+isin80˚)
Z1.Z2 = 5(cos25˚+isin25˚). 2(cos80˚+isin80˚)
Z1.Z2 = 10{(cos25˚cos80˚ + isin25˚cos80˚+i^2sin25˚sin80˚) }
Z1.Z2 =10{(cos25˚cos80˚- sin25˚sin80˚+ i(cos25˚sin80˚+sin25˚cos80˚))}
(i^2 = -1)
Cos(A+B) = cosAcosB – sinAsinB
Sin(A+B) = sinAcosB + cosAsinB
Z1.Z2 = 10(cos(25˚+80˚) +isin(25˚+80˚)
Z1.Z2 = 10(cos105˚+ isin105˚)
C would be chur answer i hoped i helped
total cost = membership +cost per class* number of classes
y = 275+5*x
Choice C
Answer:
x = 9.5 m
Step-by-step explanation:
Given:
This problem is based on 2D motion kinematics equations:



At maximum height:

Components of initial velocity:


To find time to reach maximum height:
Plugging in the known values:
0 = 4.10 - 9.8t


Total time = 2t = 2(0.418) = 0.836 s
to find horizontal distance covered:

Answer: Quotient
Step-by-step explanation: