All categories

3 years ago

Please please someone help

Mathematics

2 answers:

natka813 [3]3 years ago

7 0

The answer is the first one:

bc its not growing by a (-)1/2 and the 3rd one just doesnt make sense

PIT_PIT [208]3 years ago

4 0

The vertex form is y = x
Standard form is x + y = number
Move x to the other side
-x + y = 0
The coefficient on x cannot be negative so multiply the whole equation by -1.
x - y = 0

You might be interested in

Solve the following equation: (n + 1) + 3(n - 1) = 2(n - 1)(n + 1)

Mnenie [13.5K]

Answer:

n = 0, n =2

Step-by-step explanation:

Given

(n + 1) + 3(n - 1) = 2(n - 1)(n + 1) ← distribute parenthesis on both sides

n + 1 + 3n - 3 = 2(n² - 1), that is

4n - 2 = 2n² - 2 ( subtract 4n - 2 from both sides )

0 = 2n² - 4n ← factor out 2n from each term )

0 = 2n(n - 2)

Equate each factor to zero and solve for n

2n = 0 ⇒ n = 0

n - 2 = 0 ⇒ n = 2

7 0

3 years ago

Calcula la longitud en YARDAS de

tatiyna

Answer:

Las longitudes solicitadas en yardas son:

Trayecto A = 109.361 yardas.
Trayecto B = 20.231785 yardas.

Step-by-step explanation:

Para hacer la conversión de unidades que requieres en el ejercicio, debes saber que:

1 metro = 1.09361 yardas

Con ese factor de conversión tú puedes hacer reglas de tres para calcular las medidas que requieres. En el caso del trayecto A:

Si:

1 metro = 1.09361 yardas
100 metros = X

Entonces:

$x=\frac{100m *1.09361yardas}{1m}$

Cancelamos metros y obtenemos:

x = 100 * 1.09361 yardas
x = 109.361 yardas

En este caso, el trayecto A en yardas corresponde a 109.361 yardas. El mismo procedimiento puede aplicarse para el trayecto B:

Si:

1 metro = 1.09361 yardas
18.50 metros = X

Entonces:

$x = \frac{18.50m*1.09361yardas}{1m}$

Cuando se cancelan los metros se obtiene:

x = 18.50 * 1.09361 yardas
x = 20.231785 yardas

Así, el trayecto B en yardas corresponde a 20.231785 yardas.

4 0

3 years ago

He loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a p

chubhunter [2.5K]

Complete question :

The loudness of a jack hammer is 96 dB. Its sound intensity is about 0.004.

The loudness of a compactor is 94 dB. Its sound intensity is about 0.0025.

The sound intensity of the jack hammer is about 1.6 times the sound intensity of the compactor.

The loudness of a pile driver is 112 dB. About how many times the sound intensity of the jackhammer is the sound intensity of a pile driver? Round to the nearest ten.

Answer:

Step-by-step explanation:

Given that:

Sound intensity of jackhammer = 0.004

Sound intensity of compactor = 0.0025

Sound intensity of jackhammer is about 1.6 times the sound intensity of a compactor

Each factor of 10 in intensity corresponds to 10dB

Pile driver with loudness of 112dB ; 112 / 10 = 11.2

Hence, 10^11.2 = 1.58489 * 10^11

Hence, sound intensity (I) in watts per m²

I = 1.58489 * 10^11 * 10^-12

I = 1.58489 * 10-1

I = 0.158489

Comparing the intensity of pile driver and jackhammer :

Intensity of piledriver / Intensity of jackhammer

0.158489 / 0.004

= 39.622

= 40 (nearest ten)

3 0

3 years ago

Read 2 more answers

Simplify . 3 sqrt 10 + 7 sqrt 15 - 6 sqrt 10 -4 sqrt 15

andre [41]

Take the like terms of the equation.

$3 \sqrt{10} - 6 \sqrt{10}$

$7 \sqrt{15} - 4 \sqrt{15}$

Subtract those like terms together.

$3 \sqrt{10} - 6 \sqrt{10} = -3 \sqrt{10}$

$7 \sqrt{15} - 4 \sqrt{15} = 3 \sqrt{15}$

The simplified form of this equation is $-3 \sqrt{10} + 3 \sqrt{15}$ .

6 0

3 years ago

What is the answer for 5B=5B/4+60

maks197457 [2]

Answer:

the answer would be b=16

4 0

3 years ago