11.5 beause you take the average of 12 and 11
1
-
2
Put it like that and there’s your constant
Answer:
21.5secs
Step-by-step explanation:
Given the function that models the height of an object as
h(t) = -16t^2+ 344t
The object hit the ground at h(t) = 0
Substitute
0 = -16t^2+ 344t
16t^2 = 344t
16t = 344
t = 344/16
t = 21.5
Hence it takes 21.5secs for the object to hit the ground
I believe the answer is 186.556 degrees celcius
