Question

Helllp please Find the area of The following figures. Dimensions are in centimeters.

Answer 1

Answer:

$\huge\mathfrak\red{Answer...} \\ \\ area \: of \: square \: = side {}^{2} \\ \\ side = \: 6 \: cm \\ \\ area \: of \: square \: = 6 \times 6 \\ \\ area \: of \: square \: = 36 \: cm.sq \\ \\ area \: of \: semicircle \: = (1 \div 2)\pi \: r {}^{2} \\ \\ radius = 2 \: cm \\ \\ area \: of \: semicircle = 6.28 \: cm.sq \\ \\ area \: of \: whole \: figure \: = 36 + 6.28 \\ \\ area = 42.28 \: cm.sq$

Answer 2

Answer:

Seperate the shapes!

Step-by-step explanation:

CIRCLE

First we want to find the area of the circle which would be:

\pi r^{2}

3.14159265359 x 2^{2}

3.14159265359 x 4cm

= 12.5663706144cm^{2} /2 (must divide by two because it is half of a circle)

= 6.28318530718cm^{2}

RECTANGLE/SQUARE

Find the area of the square.

AREA = L x W

Length =  2cm + ?

Width = 6cm

To find the length we must use the diameter of the circle (which is the radius but times it by 2)

To find diameter: r x 2

= 2cm x 2

= 4cm

Length = 4 + 2 = 6cm

Width = 6 cm

Area (Length x Width) = 6cm x 6cm

= 36cm^{2}

TOTAL AREA:

Just add the area of the circle and the area of the square together.

Area total = 36cm^{2} + 6.28318530718cm^{2}

= 42.2831853072cm^{2}

* Also round your total answer to the nearest tenth or hundreth if needed to do so.