PLEASE HELP FIRST PERSON GETS MARKED BRAINLYEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!A map of a town is drawn on a coordinate grid
where each unit represents a mile. The middle school is located at (3, –8). Marcy’s house is at (3, 2) and Henry’s house is at (8, –8). Does Marcy or Henry live closer to the school? Justify your answer and show any calculations used
2 answers:
Henry's House is closer to the middle school. As you can see in the graph; Henry's house is only a couple of miles away, while Marcy's house is very far from the house.
The point of Henry's house is closer to the point of the middle school than Marcy's house. One way to justify is through the distance formula.
The distance between the middle school and Marcy's house is 10, while the distance between the middle school and Henry's house is 5.
Henry's house is exactly 1/2 the distance from Marcy's house to the middle school.
The distance between the middle school and Marcy's house is 10, while the distance between the middle school and Henry's house is 5.
Henry's house is exactly 1/2 the distance from Marcy's house to the middle school.
You might be interested in
L = hours for the slower pump to fill the pool
L - 5 = hours for the high power pump, since it can do it in 5 hours less.
since the slower pump takes L hours, the faster pump takes then L - 5 hours.
we know both pumps together take 3 hours to do <u>half of the pool</u>, so that means that to fill up <u>the whole pool it takes them 6 hours</u>.
since the slower pump can do it alone in L hours, in 1 hour it has done 1/L of the whole thing.
likewise, since the faster pump can do it in L-5 hours, in 1 hour alone it has done 1/(L-5) of the whole job.
now, we can't use L = 2, because, the whole job by both is done in 6 hours, there's no way the slower pump can do it in less than that, so L = 15.
now if L = 15, then L - 5 = 10.
Answer:
The solution set can be given as:
Step-by-step explanation:
Given function:
To find the domain of the function in set notation.
Solution:
For the function to exist the denominator must be ≠ 0
We have the denominator which cannot be = 0.
Thus, we can find the domain of the function using the above relation.
The function will not exist when:
Solving for
Subtracting both sides by 6.
Dividing both sides by 2.
∴
Thus, the function will not exist at . This means it has all real number solutions except -3.
The solution set can be given as: