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RUDIKE [14]
3 years ago
8

The Answer to number 72

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0
First we want to calculate at what height and at what time rocket stops ascending.
h' = 256 - 32t = 0
32t = 256
t = 8

h = 256*8 - 16*8^2
h = 1024

Now we want to find time at which it gets 200 feet that means our equation is:
200 = 256t - 16*t^2
-16*t^2 + 256t - 200 = 0  

t1 = 0.82s
t2 = 15.17s

time t1 is when rocket is ascending and t2 when it is descending therefore answer is t2
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