Answer:
The solution set can be given as:

Step-by-step explanation:
Given function:

To find the domain of the function in set notation.
Solution:
For the function
to exist the denominator must be ≠ 0
We have the denominator
which cannot be = 0.
Thus, we can find the domain of the function using the above relation.
The function
will not exist when:

Solving for 
Subtracting both sides by 6.


Dividing both sides by 2.

∴ 
Thus, the function will not exist at
. This means it has all real number solutions except -3.
The solution set can be given as:
