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3 years ago

How would I solve this? Thank you to whoever answers.

Mathematics

1 answer:

melomori [17]3 years ago

7 0

I think by adding the numbers and dividing how many numbers are there to get the answer

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Instructions

Ierofanga [76]

Answer:

Some one help im so confused...

Step-by-step explanation:

4 0

2 years ago

Write an expression to represent the sum of three times the square of a number and -7 . In your expression what is the value of

stich3 [128]

Answer:

Step-by-step explanation:

3x^2-7

8 0

2 years ago

a loaded truck is traveling 20 mph faster than a freight train. In the time it takes the train to travel 160 miles, the truck tr

almond37 [142]

Speed of trucks= x speed of trains =x-30 A loaded

6 0

3 years ago

Simplify the expression.<br><br> (−2g5h2)5

vampirchik [111]

I am sure you are trying to type

$( - 2 {g}^{5} {h}^{2} {)}^{5}$
If that is it, then you should recall the law of exponents which says,

$({a}^{m} {)}^{n} = {a}^{mn}$
Let us share the exponent for each of them.

$( - 2 {g}^{5} {h}^{2} {)}^{5} = ( { - 2)}^{5} ( { {g}^{5}) }^{5} ( { {h}^{2}) }^{5}$
We now apply the law,

$( - 2 {g}^{5} {h}^{2} {)}^{5} = ( { - 2)}^{5} ( { {g}^{5 \: \times 5}) }^{} ( { {h}^{2 \times 5}) }^{}$
We now simplify to obtain,

$( - 2 {g}^{5} {h}^{2} {)}^{5} = -32 {g}^{25} {h}^{10}$

If that is not the expression let me know so I will know how to help you

4 0

2 years ago

In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne

Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

$H_0: \bar x =12.7\\H_a: \bar x >12,7$

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = $\frac{6}{\sqrt{1000} } \\=0.1897$

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

5 0

2 years ago